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In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion?
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In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solut...
Calculating the Ratio of NaNO3 and Ca(MO3)2 Solutions:
- Let x be the ratio of NaNO3 to Ca(MO3)2 solutions.
- The negative ion in NaNO3 is NO3- and in Ca(MO3)2 is MO3-.

Concentration of Negative Ion:
- The concentration of NO3- in the resulting solution = 0.2x + 0.1(2x) = 0.2x + 0.2x = 0.4x
- The concentration of MO3- in the resulting solution = 0.1(2x) = 0.2x

Given Condition:
- The concentration of Negative Ion is 50% greater than the concentration of Positive Ion.
- 0.4x = 1.5 * 0.2x
- 0.4x = 0.3x
- x = 0.75

Ratio of NaNO3 to Ca(MO3)2 Solutions:
- The ratio of NaNO3 to Ca(MO3)2 solutions should be 0.75 : 2 = 3 : 8.
By mixing NaNO3 and Ca(MO3)2 solutions in a ratio of 3:8, the resulting solution will have the concentration of the Negative Ion 50% greater than the concentration of the Positive Ion.
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In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion?
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In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In what ratio should you make 0.2 molar NaNO3 and 0.1 M Ca(MO3)2 solution so that in resulting solution the concentration of Negative Ion is 50% greater than the concentration of positive ion?.
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