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Consider a function f(x,y) = x3 + y3, where y represents a parabolic curve x2 + 1. The total derivative of f with respect to x, at x =1 is _______.
    Correct answer is between '27.0,27.0'. Can you explain this answer?
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    Consider a function f(x,y)= x3 + y3, where y represents a parabolic cu...
    Introduction:
    In this problem, we are given a function f(x, y) = x^3 * y^3, where y represents a parabolic curve x^2 - 1. We need to find the total derivative of f with respect to x at x = 1.

    Step 1: Finding the partial derivative of f with respect to x:
    To find the total derivative of f with respect to x, we first need to find the partial derivative of f with respect to x. The partial derivative of f with respect to x can be found by differentiating f(x, y) with respect to x, while treating y as a constant.

    Let's differentiate f(x, y) = x^3 * y^3 with respect to x:

    ∂f/∂x = ∂(x^3 * y^3)/∂x

    Using the power rule of differentiation, we get:

    ∂f/∂x = 3x^2 * y^3

    Step 2: Finding the partial derivative of f with respect to y:
    Next, we need to find the partial derivative of f with respect to y. The partial derivative of f with respect to y can be found by differentiating f(x, y) with respect to y, while treating x as a constant.

    Let's differentiate f(x, y) = x^3 * y^3 with respect to y:

    ∂f/∂y = ∂(x^3 * y^3)/∂y

    Using the power rule of differentiation, we get:

    ∂f/∂y = 3x^3 * y^2

    Step 3: Finding the total derivative of f with respect to x:
    The total derivative of f with respect to x can be found using the chain rule. It is given by:

    df/dx = ∂f/∂x + (∂f/∂y * dy/dx)

    Since y represents a parabolic curve x^2 - 1, we can substitute y = x^2 - 1 in the partial derivatives ∂f/∂x and ∂f/∂y.

    ∂f/∂x = 3x^2 * (x^2 - 1)^3
    ∂f/∂y = 3x^3 * (x^2 - 1)^2

    Next, we need to find dy/dx. Taking the derivative of y = x^2 - 1 with respect to x, we get:

    dy/dx = 2x

    Substituting the values of ∂f/∂x, ∂f/∂y, and dy/dx in the total derivative equation, we get:

    df/dx = 3x^2 * (x^2 - 1)^3 + 3x^3 * (x^2 - 1)^2 * 2x

    Simplifying this expression, we get:

    df/dx = 3x^2 * (x^2 - 1)^3 + 6x^4 * (x^2 - 1)^2

    Step 4: Evaluating the total derivative at x = 1:
    To find the total derivative of f with respect to x at x =
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    Consider a function f(x,y)= x3 + y3, where y represents a parabolic curve x2 + 1. The total derivative of f with respect to x, at x =1 is _______.Correct answer is between '27.0,27.0'. Can you explain this answer?
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    Consider a function f(x,y)= x3 + y3, where y represents a parabolic curve x2 + 1. The total derivative of f with respect to x, at x =1 is _______.Correct answer is between '27.0,27.0'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Consider a function f(x,y)= x3 + y3, where y represents a parabolic curve x2 + 1. The total derivative of f with respect to x, at x =1 is _______.Correct answer is between '27.0,27.0'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a function f(x,y)= x3 + y3, where y represents a parabolic curve x2 + 1. The total derivative of f with respect to x, at x =1 is _______.Correct answer is between '27.0,27.0'. Can you explain this answer?.
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