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A star-connected alternator supplies a delta-connected load. The impedance of the load branch is (8 + j6) ohm/phase. Determine the power factor.
  • a)
    0.6
  • b)
    0.8
  • c)
    0.57
  • d)
    0.9
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A star-connected alternator supplies a delta-connected load. The imped...
Impedance of the load branch
- The impedance of the load branch is given as (8 + j6) ohm/phase.

Power factor
- To determine the power factor, we need to calculate the impedance angle of the load branch.
- The impedance angle can be calculated using the formula: θ = arctan(Imaginary part/Real part).
- In this case, θ = arctan(6/8) ≈ 36.87 degrees.

Power factor formula
- The power factor is given by the cosine of the impedance angle.
- Power factor (PF) = cos(θ) = cos(36.87) ≈ 0.8.
Therefore, the power factor of the delta-connected load supplied by the star-connected alternator is approximately 0.8. So, the correct answer is option 'B'.
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Community Answer
A star-connected alternator supplies a delta-connected load. The imped...
The overall power factor is defined as the cosine of the angle between the voltage and current. In AC circuits, the power factor is also defined as the ratio of the real power flowing to the load to the apparent power in the circuit. Hence power factor can also be defined as the ratio of watts to volt-amperes.
The load is delta connected having impedance (8 + j6) Ω
Power factor
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A star-connected alternator supplies a delta-connected load. The impedance of the load branch is (8 + j6) ohm/phase. Determine the power factor.a)0.6b)0.8c)0.57d)0.9Correct answer is option 'B'. Can you explain this answer?
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