Can you explain the answer of this question below:125 ml of 8% w/w NaO...
Bro it's nice after so many times I have seen anyone coding in asking questions
Can you explain the answer of this question below:125 ml of 8% w/w NaO...
Calculation of moles of NaOH and HCl:
Moles of NaOH = (8/100) x 125/40 = 0.25
Moles of HCl = (10/100) x 125/36.5 = 0.342
Since moles of HCl > moles of NaOH, all the NaOH will be consumed in the reaction and there will be some HCl remaining.
HCl + NaOH → NaCl + H2O
After the reaction, the final volume of the solution will be 125 + 125 = 250 mL.
Concentration of HCl in the final solution:
Concentration of HCl = (0.342 moles / 0.25 L) x (1 L / 0.25 L) x (1000 mL / 1 L) = 136.8 mL/L
pH of the final solution:
pH = -log[H+]
[H+] = concentration of HCl = 136.8 mM
pH = -log(136.8 x 10^-3) = 2.86
Since the pH of the final solution is less than 7, it is acidic. Therefore, the correct answer is option 'A' (acidic).