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If the solubility product of AB2 is 3.20 × 10-11 M3, then the solubility of AB2 in pure water is _____ × 10-4 mol L-1. [Assuming that neither kind of ion reacts with water]
[Answer in 2 significant digits]
Correct answer is '2'. Can you explain this answer?
Most Upvoted Answer
If the solubility product of AB2is 3.20 × 10-11M3, then the solu...
The solubility product (Ksp) is a measure of the extent to which a compound can dissolve in water. It is calculated by multiplying the concentrations of the ions present in a saturated solution.

If the solubility product of AB2 is given as 3.20, it means that the product of the concentrations of the ions A and B in a saturated solution of AB2 is equal to 3.20.

The solubility product expression for the compound AB2 can be written as:

Ksp = [A]^2[B]

where [A] and [B] are the concentrations of the ions A and B, respectively.

Without additional information, it is not possible to determine the specific concentrations of A and B in the saturated solution or the units of the solubility product.
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Community Answer
If the solubility product of AB2is 3.20 × 10-11M3, then the solu...

KSP = S1 × (2s)2 = 4s3
3.2 × 10-11 = 4 × S3
S = 2 × 10-4 M/L
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If the solubility product of AB2is 3.20 × 10-11M3, then the solubility of AB2in pure water is _____ × 10-4mol L-1. [Assuming that neither kind of ion reacts with water][Answer in 2 significant digits]Correct answer is '2'. Can you explain this answer?
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