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A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet, while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-°C) (1 cal = 4.2 x 107 ergs) is close to
  • a)
    83.3°C
  • b)
    87.5°C
  • c)
    38.4°C
  • d)
    119.2°C
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fi...
Given Data:
- Mass of the bullet (m) = 5 g = 0.005 kg
- Velocity of the bullet (v) = 210 m/s
- Specific heat of the material of the bullet (c) = 0.030 cal/(g-°C) = 0.030 x 4.2 x 10^7 J/(kg-°C)

Calculation:
1. Calculate the initial kinetic energy of the bullet:
- Kinetic energy (KE) = 0.5 * m * v^2
- KE = 0.5 * 0.005 * 210^2
- KE = 0.5 * 0.005 * 44100
- KE = 110.25 J
2. Half of the kinetic energy is converted into heat in the bullet:
- Heat energy in the bullet (Q1) = 0.5 * KE
- Q1 = 0.5 * 110.25
- Q1 = 55.125 J
3. Calculate the rise in temperature of the bullet:
- Q1 = m * c * ΔT
- 55.125 = 0.005 * (0.030 x 4.2 x 10^7) * ΔT
- ΔT = 55.125 / (0.005 * 0.030 x 4.2 x 10^7)
- ΔT ≈ 87.5°C
Therefore, the rise in temperature of the bullet is approximately 87.5°C. Hence, option 'B' is correct.
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Community Answer
A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fi...
Given data:
Mass of the bullet, m = 5 g
Velocity of the bullet v = 210 m/s
Specific heat of bullet material, s = 0.030 cal/(g-°C) = 30 cal/(kg-°C)
Considering the given data,
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A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet, while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-°C) (1 cal = 4.2 x 107 ergs) is close toa)83.3°Cb)87.5°Cc)38.4°Cd)119.2°CCorrect answer is option 'B'. Can you explain this answer?
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A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet, while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-°C) (1 cal = 4.2 x 107 ergs) is close toa)83.3°Cb)87.5°Cc)38.4°Cd)119.2°CCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet, while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-°C) (1 cal = 4.2 x 107 ergs) is close toa)83.3°Cb)87.5°Cc)38.4°Cd)119.2°CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet, while the other half is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal/(g-°C) (1 cal = 4.2 x 107 ergs) is close toa)83.3°Cb)87.5°Cc)38.4°Cd)119.2°CCorrect answer is option 'B'. Can you explain this answer?.
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