Can you explain the answer of this question below:A:4B:1/4C:2D:none of these.The answer is a.

Question

Answer

->>Sintheta=3/5....-> sectheta=1/costheta...-> tantheta=sintheta/costheta...by substituting in the given que u will get...1+sintheta/1-sintheta....at last by solving u will get ans 4...HOPE U GOT IT...

Answer

Answer

SinQ is 3/5. on simplifying (secQ+tanQ)/(secQ-tanQ) we get...(1+sinQ)/(1-sinQ) =(1+3/5)/(1-3/5)=(8/2)=4

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Concept: Trigonometry.Given,        5sinQ =3       SinQ  = 3/5.................(i)Now, SecQ = 1/CosQ. tanQ = SinQ /Cos Q.Now, when u will substitute the value SecQ and tanQ U will get 1+SinQ / 1-SinQ. And then from (i).Putting the value of SinQ, you will get answers 4.

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Seco =1/coso and tano= sini/coso so given changes ((1+sino)/(1-sini)=(8/5)(2/5)=4

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sin θ is 3/5.
on simplifying:
(secθ + tanθ)/(secθ - tanθ)
We get, (1+sin θ)/(1-sin θ)
=(1+3/5)/(1-3/5)
=(8/2)
=4

Answer

If 5sin@ is 5 then sin@=3/5I.e. @=37degreeputting the value of @ in expression we get 4

Answer

Sin0is3/5

on simplifying

(sec0+tan0) (sen0-tan0)

we get (1+sen 0) (1_sen 0)

(1+3/5) (1_3/5)

8/2

4

Answer

5sinx=3 =sinx=3/5 as sinx =p/h p=3; h=5 by pythegorus theorem b=4 then secx=5/4 and tanx =3/4 acc. to question 5/4+3/4 5/4-3/4 =4

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I will write x in terms of thetaSin x=3/5If we use the formulaCos^2x=1-sin^2x             =1-(3/5)^2             =1-9/25             =16/25Cosx=4/5Sinx/cosx=3/4Tan x=3/4Sec x=1/cos x          =1/4/5 Sec x=5/4Sec x +tan x/sec x-tanx5/4+3/4/5/4-3/48/4/2/42/1/2=4

Answer

5sin=3 ,sin=3/5 =P/H . P^2=B^2+H^2 using this formulaWe get,B=4sec=H/B=5/4tan =P/B =3/4Put the values in questionWe get answer 4.

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