Class 6 Exam > Class 6 Questions > If LINGER is coded as !@#$%& and ANGER is...
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If LINGER is coded as !@#$%& and ANGER is coded as *#$%&, then how will you code GINGER ?
- a)$@#$%&
- b)!@#$%&
- c)!@#$%
- d)$#$%&
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If LINGER is coded as !@#$%& and ANGER is coded as *#$%&, then...
The code of different letters is given below as:
L -- !
I -- @
N --- #
G --- $
E --- %
R ----- &
Similarly, we can find out the code for GINGER.
GINGER = $@#$%&
L -- !
I -- @
N --- #
G --- $
E --- %
R ----- &
Similarly, we can find out the code for GINGER.
GINGER = $@#$%&
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Community Answer
If LINGER is coded as !@#$%& and ANGER is coded as *#$%&, then...
Understanding the Coding Scheme
To decode the given words, we need to analyze how each letter in the words corresponds to the symbols in their coded versions.
Code Analysis
- LINGER is coded as !@#$%&
Let's break it down:
- L -> !
- I -> @
- N -> #
- G -> $
- E -> %
- R -> &
- ANGER is coded as *#$%&
Analyzing this:
- A -> *
- N -> #
- G -> $
- E -> %
- R -> &
From the above, we can see that:
- The letters N, G, E, and R are consistently coded as #, $, %, and & respectively.
Decoding GINGER
Now, let's decode the word GINGER using the symbols we have identified:
- G -> $
- I -> @
- N -> #
- G -> $
- E -> %
- R -> &
Putting these together, we get:
- GINGER -> $@$#$%&
However, to match the coding style of the options provided, we can see that:
- G -> $ (Position 1)
- I -> @ (Position 2)
- N -> # (Position 3)
- G -> $ (Position 4)
- E -> % (Position 5)
- R -> & (Position 6)
The correct sequence for GINGER becomes:
- $@#$%&
Conclusion
Hence, the code for GINGER is $@#$%&, which corresponds to option A.
To decode the given words, we need to analyze how each letter in the words corresponds to the symbols in their coded versions.
Code Analysis
- LINGER is coded as !@#$%&
Let's break it down:
- L -> !
- I -> @
- N -> #
- G -> $
- E -> %
- R -> &
- ANGER is coded as *#$%&
Analyzing this:
- A -> *
- N -> #
- G -> $
- E -> %
- R -> &
From the above, we can see that:
- The letters N, G, E, and R are consistently coded as #, $, %, and & respectively.
Decoding GINGER
Now, let's decode the word GINGER using the symbols we have identified:
- G -> $
- I -> @
- N -> #
- G -> $
- E -> %
- R -> &
Putting these together, we get:
- GINGER -> $@$#$%&
However, to match the coding style of the options provided, we can see that:
- G -> $ (Position 1)
- I -> @ (Position 2)
- N -> # (Position 3)
- G -> $ (Position 4)
- E -> % (Position 5)
- R -> & (Position 6)
The correct sequence for GINGER becomes:
- $@#$%&
Conclusion
Hence, the code for GINGER is $@#$%&, which corresponds to option A.
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If LINGER is coded as !@#$%& and ANGER is coded as *#$%&, then how will you code GINGER ?a)$@#$%&b)!@#$%&c)!@#$%d)$#$%&Correct answer is option 'A'. Can you explain this answer?
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