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Find the equation of the normal at a point on the curve x2 = 4y which passes through the point (1.2)
  • a)
    y = x - 1
  • b)
    2x + y = 4
  • c)
    x-y = 3
  • d)
    x+y = 3
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Find the equation of the normal at a point on the curve x2 = 4ywhich p...
The equation of the given curve is  x2 = 4y
Differentiating w.r.t.  x, we get 
Now, slope of the tangent at (h,k) is given by, 
Thus, slope of the normal at 
Therefore, the equation of normal at 

Since it passes through the point  (1,2) we have 
now(h,k) lies on the curve  x2 = 4y, so we have h2 = 4k   ...(3)
Solving (2) and (3), we get ℎ=2 and k= 1
From (1), the required equation of the normal is: 
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Find the equation of the normal at a point on the curve x2 = 4ywhich passes through the point (1.2)a)y = x - 1b)2x + y = 4c)x-y = 3d)x+y = 3Correct answer is option 'D'. Can you explain this answer?
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Find the equation of the normal at a point on the curve x2 = 4ywhich passes through the point (1.2)a)y = x - 1b)2x + y = 4c)x-y = 3d)x+y = 3Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find the equation of the normal at a point on the curve x2 = 4ywhich passes through the point (1.2)a)y = x - 1b)2x + y = 4c)x-y = 3d)x+y = 3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the normal at a point on the curve x2 = 4ywhich passes through the point (1.2)a)y = x - 1b)2x + y = 4c)x-y = 3d)x+y = 3Correct answer is option 'D'. Can you explain this answer?.
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