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A scientist was weighing each of 30 fishes. Their mean weight worked out is 30 g and standard deviation is 2 g. Later, it was found that the measuring scale was misaligned and always under-reported every fish's weight by 2 g. The correct mean and standard deviation (in g) of fishes, are respectively
  • a)
    32 and 2
  • b)
    32 and 4
  • c)
    28 and 2
  • d)
    28 and 4
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A scientist was weighing each of 30 fishes. Their mean weight worked o...
Since mean (X + b) = E( X + b) = E(X) + b and Var (X + b) = Var X,
We get correct mean as 30 + 2 = 32 g and (s.d.) standard deviation as 2 g.
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Most Upvoted Answer
A scientist was weighing each of 30 fishes. Their mean weight worked o...
Given Data:
- Mean weight of 30 fishes = 30 g
- Standard deviation of the weights = 2 g
- Error in measurement = 2 g under-reporting

Calculating Correct Mean:
Since the measuring scale under-reported each fish's weight by 2 g, we need to add 2 g to each fish's weight to get the correct mean weight.
Correct Mean = 30 g (original mean) + 2 g (error) = 32 g

Calculating Correct Standard Deviation:
The standard deviation remains unchanged when a constant value is added to each data point. Therefore, the correct standard deviation remains the same as the original standard deviation.
Correct Standard Deviation = 2 g

Final Answer:
Therefore, the correct mean weight of the fishes is 32 g and the correct standard deviation is 2 g. Hence, option 'A' (32 and 2) is the correct answer.
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A scientist was weighing each of 30 fishes. Their mean weight worked out is 30 g and standard deviation is 2 g. Later, it was found that the measuring scale was misaligned and always under-reported every fishs weight by 2 g. The correct mean and standard deviation (in g) of fishes, are respectivelya)32 and 2b)32 and 4c)28 and 2d)28 and 4Correct answer is option 'A'. Can you explain this answer?
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A scientist was weighing each of 30 fishes. Their mean weight worked out is 30 g and standard deviation is 2 g. Later, it was found that the measuring scale was misaligned and always under-reported every fishs weight by 2 g. The correct mean and standard deviation (in g) of fishes, are respectivelya)32 and 2b)32 and 4c)28 and 2d)28 and 4Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A scientist was weighing each of 30 fishes. Their mean weight worked out is 30 g and standard deviation is 2 g. Later, it was found that the measuring scale was misaligned and always under-reported every fishs weight by 2 g. The correct mean and standard deviation (in g) of fishes, are respectivelya)32 and 2b)32 and 4c)28 and 2d)28 and 4Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A scientist was weighing each of 30 fishes. Their mean weight worked out is 30 g and standard deviation is 2 g. Later, it was found that the measuring scale was misaligned and always under-reported every fishs weight by 2 g. The correct mean and standard deviation (in g) of fishes, are respectivelya)32 and 2b)32 and 4c)28 and 2d)28 and 4Correct answer is option 'A'. Can you explain this answer?.
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