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The velocity of an object is changing with time and relation is given by following equation v=2t+3t(square) calculate the position of object from the origin at t=2s assume particle to be at origin t=0?
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The velocity of an object is changing with time and relation is given ...
Calculation of position of object from the origin
Given Parameters
- Initial position of the particle is at the origin
- The velocity of the particle changes with time and is given by v = 2t + 3t²
- The time is given as t = 2s
Calculation of position of the particle
To calculate the position of the particle at t = 2s, we need to integrate the velocity function. The integration of the given velocity function is:
s = ∫vdt = ∫(2t + 3t²)dt = (2t²/2) + (3t³/3) + C
where C is the constant of integration.
At t = 0, the initial position of the particle is at the origin. Therefore, we can find the value of C using this condition.
s = (2t²/2) + (3t³/3) + C
At t = 0, s = 0
Therefore, C = 0
Substituting the value of C in the equation for position, we get:
s = (2t²/2) + (3t³/3)
At t = 2s, the position of the particle is:
s = (2(2)²/2) + (3(2)³/3) = 8 + 16 = 24m
Conclusion
Therefore, the position of the particle from the origin at t = 2s is 24m.
Community Answer
The velocity of an object is changing with time and relation is given ...
D{2t+3t}^2 /dv = 50 x t = when t=2 then position is 100 =when t=0 then position would be 0 or at rest.
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The velocity of an object is changing with time and relation is given by following equation v=2t+3t(square) calculate the position of object from the origin at t=2s assume particle to be at origin t=0?
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