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The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____ J. (in integers)
(Given R = 8.31 J/mol.K)
Correct answer is '7479'. Can you explain this answer?
Verified Answer
The total internal energy of two mole monoatomic ideal gas at temperat...
U = nCvT
= 2 × 3/2 R × 300
= 900 R = 900 × 8.31 = 7479 J
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Most Upvoted Answer
The total internal energy of two mole monoatomic ideal gas at temperat...

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Calculating the total internal energy of two mole monoatomic ideal gas at temperature T = 300 K

- Given information:
- T = 300 K
- R = 8.31 J/mol.K
- Number of moles (n) = 2

- The formula to calculate the total internal energy of an ideal gas is:
- Total internal energy (U) = n * Cv * T
- Where Cv is the molar specific heat at constant volume

- For a monoatomic ideal gas, Cv = (3/2)R
- So, Cv = (3/2) * 8.31 = 12.465 J/mol.K

- Now, substituting the values in the formula:
- U = 2 * 12.465 * 300
- U = 7479 J

Therefore, the total internal energy of two mole monoatomic ideal gas at temperature T = 300 K is 7479 J.
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The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____ J. (in integers)(Given R = 8.31 J/mol.K)Correct answer is '7479'. Can you explain this answer?
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