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The disintegration rate of a certain radioactive sample at any instant is 4,250 disintegrations per minute. 10 minutes later, the rate becomes 2,250 disintegrations per minute. The approximate decay constant is:
(Take log10 1.88 = 0.274)
  • a)
    0.02 min-1
  • b)
    2.7 min-1
  • c)
    0.063 min-1
  • d)
    6.3 min-1
Correct answer is option 'C'. Can you explain this answer?
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The disintegration rate of a certain radioactive sample at any instant...
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The disintegration rate of a certain radioactive sample at any instant...
Given Data:
- Initial disintegration rate = 4,250 disintegrations per minute
- Disintegration rate after 10 minutes = 2,250 disintegrations per minute

Calculating Decay Constant:
- Using the formula for radioactive decay: N(t) = N₀ * e^(-λt), where N(t) is the quantity of the substance at time t, N₀ is the initial quantity, λ is the decay constant, and t is the time elapsed.
- At t = 0, N(t) = 4,250 disintegrations per minute
- At t = 10 minutes, N(t) = 2,250 disintegrations per minute
- Substituting the values into the formula, we get: 2,250 = 4,250 * e^(-10λ)
- Solving for λ, we get: λ ≈ 0.063 min^-1
Therefore, the approximate decay constant for the radioactive sample is 0.063 min^-1, which corresponds to option 'C'.
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The disintegration rate of a certain radioactive sample at any instant is 4,250 disintegrations per minute. 10 minutes later, the rate becomes 2,250 disintegrations per minute. The approximate decay constant is:(Take log101.88 = 0.274)a)0.02 min-1b)2.7 min-1c)0.063 min-1d)6.3 min-1Correct answer is option 'C'. Can you explain this answer?
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The disintegration rate of a certain radioactive sample at any instant is 4,250 disintegrations per minute. 10 minutes later, the rate becomes 2,250 disintegrations per minute. The approximate decay constant is:(Take log101.88 = 0.274)a)0.02 min-1b)2.7 min-1c)0.063 min-1d)6.3 min-1Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The disintegration rate of a certain radioactive sample at any instant is 4,250 disintegrations per minute. 10 minutes later, the rate becomes 2,250 disintegrations per minute. The approximate decay constant is:(Take log101.88 = 0.274)a)0.02 min-1b)2.7 min-1c)0.063 min-1d)6.3 min-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The disintegration rate of a certain radioactive sample at any instant is 4,250 disintegrations per minute. 10 minutes later, the rate becomes 2,250 disintegrations per minute. The approximate decay constant is:(Take log101.88 = 0.274)a)0.02 min-1b)2.7 min-1c)0.063 min-1d)6.3 min-1Correct answer is option 'C'. Can you explain this answer?.
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