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Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C..

Solutions for Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. defined & explained in the simplest way possible. Besides giving the explanation of Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C., a detailed solution for Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. has been provided alongside types of Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. theory, EduRev gives you an ample number of questions to practice Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let 'N' be the number density of free electrons, each of mass 'm'. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency 'wP' which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as 'e' and the permittivity as 'ε0', use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C. tests, examples and also practice Class 11 tests.