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Can you explain the answer of this question below:
The osmotic pressure of a 0.010 M MgSO4 solution at 500 K is 0.82 atm. Calculate , the van’t Hoff factor, for this MgSO4 solution.
  • A:
    3
  • B:
    2
  • C:
    1
  • D:
    4
The answer is b.
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Can you explain the answer of this question below:The osmotic pressure...
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Can you explain the answer of this question below:The osmotic pressure...
't Hoff factor (i) for MgSO4 in this solution.

We can use the van't Hoff equation to relate the osmotic pressure to the concentration and the van't Hoff factor:

π = iMRT

where π is the osmotic pressure, M is the molar concentration, R is the gas constant, and T is the temperature in kelvin.

Plugging in the given values, we get:

0.82 atm = i(0.010 M)(0.08206 L·atm/mol·K)(500 K)

Solving for i, we get:

i = 3.98

Therefore, the van't Hoff factor for MgSO4 in this solution is approximately 4.
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Can you explain the answer of this question below:The osmotic pressure...
Osmotic pressure=i×CRT.. here..-> i=vanthoff factor-> C=concentration R=0.082lit atm mol-1 K-1-> T=temp 0.82=i×0.01×0.082×500 i=1/0.5=2... vant hoff factor (i)=2...so option b.. HOPE U GOT IT..
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Can you explain the answer of this question below:The osmotic pressure of a 0.010 M MgSO4solution at 500 K is 0.82 atm. Calculate, the van’t Hoff factor, for this MgSO4solution.A:3B:2C:1D:4The answer is b.
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