Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >  Two bulbs 100W, 250 V and 200 W, 250 V are co... Start Learning for Free
Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-
a) Both bulbs will be fused
b) 200 W bulb will be fused
c) 100W bulb will be fused
d) No bulb will be fused
Correct answer is 'C'. Can you explain this answer?
Verified Answer
Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across ...
View all questions of this test
Most Upvoted Answer
Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across ...
Answer:

When two bulbs are connected in series, the total voltage across the circuit will be divided between them in proportion to their wattage. In this case, the 100W bulb will have a voltage drop of 100/300 * 500V = 166.67V, while the 200W bulb will have a voltage drop of 200/300 * 500V = 333.33V. Therefore, the 200W bulb will have a higher voltage rating and will be able to withstand the voltage better than the 100W bulb.

Explanation:

Voltage and Wattage of Bulbs:

- 100W, 250V bulb
- 200W, 250V bulb

Voltage of Line:

- 500V

Bulbs Connected in Series:

- When bulbs are connected in series, the total voltage across the circuit will be divided between them in proportion to their wattage.

Voltage Across the Bulbs:

- Voltage across 100W bulb = 100/300 * 500V = 166.67V
- Voltage across 200W bulb = 200/300 * 500V = 333.33V

Comparison of Voltage Ratings:

- The 200W bulb has a higher voltage rating and will be able to withstand the voltage better than the 100W bulb.

Conclusion:

- Therefore, when connected in series across a 500V line, the 100W bulb will be fused as it cannot withstand the voltage as well as the 200W bulb.
Free Test
Community Answer
Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across ...
A. The 100W bulb has a resistance =250×250/100=625 ohms The 200 W bulb resistance will be half above = 312.5ohms Total resistance in series - 937.5 ohms So total series current = V/R = 500/937.5 =0.533A Power dissipated in Bulb 1: I^2⋅R =( 0.533)^2×625=177.5W Power dissipated in Bulb 2 wil be half above: 88.5 W Bulb1 , a 100W unit, will eventually burnout
Explore Courses for Electrical Engineering (EE) exam
Question Description
Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer?.
Solutions for Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer?, a detailed solution for Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? has been provided alongside types of Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two bulbs 100W, 250 V and 200 W, 250 V are connected in series across a 500V line then-a)Both bulbs will be fusedb) 200 W bulb will be fusedc)100W bulb will be fusedd) No bulb will be fusedCorrect answer is 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev