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A car travels first one-third of a certain distance with a speed of 10 km/hr, the next one-third of the distance with the speed of 20 km/hr and the last one-third distance with a speed of 60 km/hr. The average speed of the car for the whole journey is

  • a)
    18 km/hr

  • b)
    24 km/hr

  • c)
    30 km/hr

  • d)
    36 km/hr

Correct answer is 'A'. Can you explain this answer?
Verified Answer
A car travels first one-third of a certain distance with a speed of 10...
Let x = total distance.   
D=RT and you want to find R (that is, the overall average speed); 
where D = Distance, R= rate or speed;

      R = D/T
      R = x/T         [total distance is x]

   Now, for each segment, T = D/R for that portion.
R = x / ( (x/3)/10 + (x/3)/20 + (x/3)/60) )[insert the distances and rates]

R = 60x / ( 6(x/3) + 3(x/3) + (x/3) )      [multiply by 1 = 60/60 to get rid of fractions]

      R = 60x / (10x/3)   [collect terms]
      R = 60 * 3/10       [cancel 'x'; to divide by fraction, invert and multiply]
      R = 18 km/hr  
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Most Upvoted Answer
A car travels first one-third of a certain distance with a speed of 10...
Let the total distance be 3x km. Now, average speed is given by 
average speed = (total distance travelled) / (total time taken)
So, let times taken for the first, second and third halves of the journeys be t1, t2, and t3 respectively. Then, 
t1 = x/10
t2 = x/20
t3 = x/60
So, average speed = x / (t1 + t2 + t3)
= x / (x/10 + x/20 + x/60)
= 3/ ((6 + 3 + 1)/60)
= (3*60)/10
= 18 km/hr
The correct option is A.
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A car travels first one-third of a certain distance with a speed of 10 km/hr, the next one-third of the distance with the speed of 20 km/hr and the last one-third distance with a speed of 60 km/hr. The average speed of the car for the whole journey isa)18 km/hrb)24 km/hrc)30 km/hrd)36 km/hrCorrect answer is 'A'. Can you explain this answer?
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