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4.4g of CO2 and 2.24 litre of Hat STP(273.15 K and 1 atm pressure)are mixed in a container.The total of molecules present in the container will be

  • a)
    6.023 × 1023

  • b)
    12.044 × 1022

  • c)
    6.023 × 1022

  • d)
    6.023 ×1024

Correct answer is 'B'. Can you explain this answer?
Verified Answer
4.4g of CO2and 2.24 litre of H2at STP(273.15 K and 1 atm pressure)are ...
Moles of CO2=4.4/44=0.1, moles of H2=2.24/22.4=0.1 ; therefore total moles of gases =0.2 and molecules are 0.2 x Na = 0.2 x 6 x10^23=1.2 x 10^23.
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Most Upvoted Answer
4.4g of CO2and 2.24 litre of H2at STP(273.15 K and 1 atm pressure)are ...
4.4g co2=.1mol
2.24l h2=.1mol
total=.1+.1=.2mol
total molecules=.2*6.022*10^23=12.044*10^22
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Community Answer
4.4g of CO2and 2.24 litre of H2at STP(273.15 K and 1 atm pressure)are ...
Number of moles of CO2 =
∵ 22.4 L of H2 has 1 mole of H2
∴ The number of moles in 2.24L 
The total moles are 0.2.
⇒ Total molecules in 0.2 moles 
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