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The following fig. shows I-V graph for a given metallic wire at two temperatures T1and T2.Then,


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  • a)
    Temperature T2 is less

  • b)
    Temperature T2 is more

  • c)
    T1 is same as T2

  • d)
    None of the above

Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The following fig. shows I-V graph for a given metallic wire at two te...
The slope of the graph = I/V
In case of T2, I/V is less. Hence, V/I (=R) is more.
Value of resistance increases with increasing temperature. 
Hence, T2 >T1.
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Most Upvoted Answer
The following fig. shows I-V graph for a given metallic wire at two te...
I=V/R where R is resistance. I/V is slope of given I V graph so slope is inversely proportional to R so the resistance of temperature T2 curve is greater. As for metals increasing temperature increases resistance. So T2 should be greater.....so that its resistance will be greater.....and slope of I V curve will be lesser.
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Community Answer
The following fig. shows I-V graph for a given metallic wire at two te...
In the given I-V graph as the coordinate of T1 is higher than the coordinate of T2, hence T2 is greater than T1.in my contrast answer b would be right.
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The following fig. shows I-V graph for a given metallic wire at two temperatures T1and T2.Then, a)Temperature T2is lessb)Temperature T2is morec)T1is same as T2d)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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