Class 11 Exam > Class 11 Questions > The vapour density of a mixture of gas A (Mol...
Start Learning for Free
The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would be
- a)25%
- b)50%
- c)75%
- d)10%
Correct answer is 'A'. Can you explain this answer?
Verified Answer
The vapour density of a mixture of gas A (Molecular mass = 40) and gas...
Let mole of B = x
V.D = 25 mole of A = 100 x
Mol. mass = 50
V.D = 25 mole of A = 100 x
Mol. mass = 50
This question is part of UPSC exam. View all Class 11 courses
Most Upvoted Answer
The vapour density of a mixture of gas A (Molecular mass = 40) and gas...
Calculation of Mole Fraction of Gas B in the Mixture
Given, vapour density of the mixture = 25
We know that,
Vapour Density = (Molecular Weight of Mixture) / 2
Therefore,
25 = (Molecular Weight of Mixture) / 2
Molecular Weight of Mixture = 50
Now, let the mole fraction of gas A in the mixture be x, and that of gas B be (1-x).
Molecular Weight of Mixture = (Molecular Weight of A) * x + (Molecular Weight of B) * (1-x)
50 = 40x + 80(1-x)
50 = 40x + 80 - 80x
30x = 30
x = 1
Therefore, mole fraction of gas A in the mixture = 1
Mole fraction of gas B in the mixture = 1-1 = 0
Hence, the mole % of gas B in the mixture would be 0, which is equivalent to 0% and the correct answer is option A.
Given, vapour density of the mixture = 25
We know that,
Vapour Density = (Molecular Weight of Mixture) / 2
Therefore,
25 = (Molecular Weight of Mixture) / 2
Molecular Weight of Mixture = 50
Now, let the mole fraction of gas A in the mixture be x, and that of gas B be (1-x).
Molecular Weight of Mixture = (Molecular Weight of A) * x + (Molecular Weight of B) * (1-x)
50 = 40x + 80(1-x)
50 = 40x + 80 - 80x
30x = 30
x = 1
Therefore, mole fraction of gas A in the mixture = 1
Mole fraction of gas B in the mixture = 1-1 = 0
Hence, the mole % of gas B in the mixture would be 0, which is equivalent to 0% and the correct answer is option A.
Community Answer
The vapour density of a mixture of gas A (Molecular mass = 40) and gas...
Vapour density= molecular mass/2
i.e., average molecular mass of the mixture=50
let us assume no. of moles of A=x and B=y
50=40x+80y/x+y
50x+50y=40x+80y
10x=30y
x=3y
%age of B
1/4*100=25%
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer?
Question Description
The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer?.
The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer?.
Solutions for The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer?, a detailed solution for The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? has been provided alongside types of The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The vapour density of a mixture of gas A (Molecular mass = 40) and gas B (Molecular mass = 80) is 25.Then mole % of gas B in the mixture would bea)25%b)50%c)75%d)10%Correct answer is 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup