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A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then: (1) (4-π)x = πr (2) x = 2r (1) 2x = r (2) 2x = (π + 4)r? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then: (1) (4-π)x = πr (2) x = 2r (1) 2x = r (2) 2x = (π + 4)r?, a detailed solution for A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then: (1) (4-π)x = πr (2) x = 2r (1) 2x = r (2) 2x = (π + 4)r? has been provided alongside types of A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then: (1) (4-π)x = πr (2) x = 2r (1) 2x = r (2) 2x = (π + 4)r? theory, EduRev gives you an
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