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Energy of a photon of green light of wavelength 5500 is (given: h = 6.62 ×10−34Js−1) approximately
- a)3.01eV
- b)2.81ev
- c)2.26 eV
- d)2.93 eV
Correct answer is 'C'. Can you explain this answer?
Most Upvoted Answer
Energy of a photon of green light of wavelength 5500 is (given: h = 6....
As we know,
the formula for energy of photon in terms of wavelength is,, E = hc/ λ
where, E = energy of photon
h = Planck's constant =
= 6.63×10-34 Js
c = speed of light
= 3×108 m/s
and lambda = wavelength
so,
E = [6.63×10-34 J. s×3×108 m/s]/5500×10-10m
= [0.36×10-26]/10-8
= 0.36×10-18
= 3.6×10-19 J
Or, 2.26ev
the formula for energy of photon in terms of wavelength is,, E = hc/ λ
where, E = energy of photon
h = Planck's constant =
= 6.63×10-34 Js
c = speed of light
= 3×108 m/s
and lambda = wavelength
so,
E = [6.63×10-34 J. s×3×108 m/s]/5500×10-10m
= [0.36×10-26]/10-8
= 0.36×10-18
= 3.6×10-19 J
Or, 2.26ev
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Community Answer
Energy of a photon of green light of wavelength 5500 is (given: h = 6....
Given:
Wavelength of green light (λ) = 5500 Å = 5500 × 10⁻¹⁰ m
Planck’s constant (h) = 6.626 × 10⁻³⁴ Js
Formula used:
Energy (E) of a photon = (hc) / λ
where,
h = Planck's constant
c = speed of light
λ = wavelength of light
Calculation:
Speed of light (c) = 3 × 10⁸ m/s
Energy (E) of a photon = (hc) / λ = (6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s) / (5500 × 10⁻¹⁰ m)
= 3.62 × 10⁻¹⁹ J
Converting energy from Joules to electron volts (eV):
1 eV = 1.6 × 10⁻¹⁹ J
Energy (E) of a photon = (3.62 × 10⁻¹⁹ J) / (1.6 × 10⁻¹⁹ J/eV) = 2.26 eV
Therefore, the energy of the photon of green light of wavelength 5500 Å is approximately 2.26 eV. Hence, option (c) is the correct answer.
Wavelength of green light (λ) = 5500 Å = 5500 × 10⁻¹⁰ m
Planck’s constant (h) = 6.626 × 10⁻³⁴ Js
Formula used:
Energy (E) of a photon = (hc) / λ
where,
h = Planck's constant
c = speed of light
λ = wavelength of light
Calculation:
Speed of light (c) = 3 × 10⁸ m/s
Energy (E) of a photon = (hc) / λ = (6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s) / (5500 × 10⁻¹⁰ m)
= 3.62 × 10⁻¹⁹ J
Converting energy from Joules to electron volts (eV):
1 eV = 1.6 × 10⁻¹⁹ J
Energy (E) of a photon = (3.62 × 10⁻¹⁹ J) / (1.6 × 10⁻¹⁹ J/eV) = 2.26 eV
Therefore, the energy of the photon of green light of wavelength 5500 Å is approximately 2.26 eV. Hence, option (c) is the correct answer.
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