If the frequencies of alleles A and a are 0.6 and 0.4 in a population at Hardy Weinberg equilibrium then if a random sample of 200 individuals taken from the population how many are expected to be heterozygousa)112b)81c)96d)105Correct answer is option 'C'. Can you explain this answer?

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If the frequencies of alleles A and a are 0.6 and 0.4 in a population at Hardy Weinberg equilibrium then if a random sample of 200 individuals taken from the population how many are expected to be heterozygous

a)
112
b)
81
c)
96
d)
105

Correct answer is option 'C'. Can you explain this answer?

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If the frequencies of alleles A and a are 0.6 and 0.4 in a population ...

Concept:

The Hardy-Weinberg equilibrium is a principle stating that the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.
When mating is random in a large population with no disruptive circumstances, the law predicts that both genotype and allele frequencies will remain constant because they are in equilibrium.

Explanation:

T
he Hardy-Weinberg equation is a mathematical equation that can be used to calculate the genetic variation of a population at equilibrium.
The equation is an expression of the principle known as Hardy-Weinberg equilibrium, which states that the amount of genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.
The Hardy-Weinberg equation is expressed as:

p2 + 2pq + q2 =1

Where p is the frequency of the 'A' allele and q is the frequency of the 'a' allele in the population.

In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
In the given question heterozygote will be 2pq X 200, i.e., 2 X 0.6 X 0.4 X 200 = 96

hence the correct answer is option 3

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