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A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?
- a)0.45 N in the direction opposite to motion.
- b)2.45 N in the direction of motion.
- c)0.45 N in the direction of motion.
- d)1.45 N in the direction opposite to motion.
Correct answer is 'C'. Can you explain this answer?
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Verified Answer
A constant force acting on a body of mass 3 kg changes its speed from ...
Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 10 s
Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:
v = u + at
∴ a = (v – u) / t
= (3.5 – 2) / 10 = 0.15 ms^-2
As per Newton’s second law of motion, force is given as:
F = ma
= 3 x 0.15 = 0.45 N
Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.
Most Upvoted Answer
A constant force acting on a body of mass 3 kg changes its speed from ...
Initial velocity = 2m/sfinal velocity = 3.5m/sv-u=ata×10=3.5-2a=1.5/10a=0.15m/s×s
as force is constant so F=maF=3×0.15=0.45N
as force is constant so F=maF=3×0.15=0.45N
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Community Answer
A constant force acting on a body of mass 3 kg changes its speed from ...
Answer:
Given:
Mass of the body (m) = 3 kg
Initial velocity (u) = 2 m/s
Final velocity (v) = 3.5 m/s
Time taken (t) = 10 s
We know that force (F) is related to mass (m), initial velocity (u), final velocity (v), and time taken (t) by the equation:
F = m(v - u) / t
Substituting the given values:
F = 3 kg * (3.5 m/s - 2 m/s) / 10 s
Simplifying the expression:
F = 3 kg * 1.5 m/s / 10 s
F = 4.5 kg m/s / 10 s
F = 0.45 N
The magnitude of the force acting on the body is 0.45 N.
Since the direction of motion of the body remains unchanged, the force is acting in the same direction as the motion of the body. Therefore, the direction of the force is in the direction of motion.
Hence, the correct answer is option (c) 0.45 N in the direction of motion.
Given:
Mass of the body (m) = 3 kg
Initial velocity (u) = 2 m/s
Final velocity (v) = 3.5 m/s
Time taken (t) = 10 s
We know that force (F) is related to mass (m), initial velocity (u), final velocity (v), and time taken (t) by the equation:
F = m(v - u) / t
Substituting the given values:
F = 3 kg * (3.5 m/s - 2 m/s) / 10 s
Simplifying the expression:
F = 3 kg * 1.5 m/s / 10 s
F = 4.5 kg m/s / 10 s
F = 0.45 N
The magnitude of the force acting on the body is 0.45 N.
Since the direction of motion of the body remains unchanged, the force is acting in the same direction as the motion of the body. Therefore, the direction of the force is in the direction of motion.
Hence, the correct answer is option (c) 0.45 N in the direction of motion.
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A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer?
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A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer?.
A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A constant force acting on a body of mass 3 kg changes its speed from 2 m/s to 3.5 m/s in 10 second. If the direction of motion of the body remains unchanged, what is the magnitude and direction of the force?a)0.45 N in the direction opposite to motion.b)2.45 N in the direction of motion.c)0.45 N in the direction of motion.d)1.45 N in the direction opposite to motion.Correct answer is 'C'. Can you explain this answer?.
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