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An electron is rotating around an infinite positive linear charge in a circle of radius of 0.1m,if the linear charge density is 1microcoloumb per metre,then find the velocity of electron in m/s.?
Verified Answer
An electron is rotating around an infinite positive linear charge in a...
Since, an electron is rotating around positive linear charge so, there will be a force of attraction among the positive charges and also since, electron is revolving in a circle there will be a centrifugal (repulsive) force acting on it.
Hence,
Centrifugal Force = Electric Force
m₍e₎ v^2 / r = e E
m₍e₎ v^2 / r = k₍e₎ Q / r^2  ----(1)
Since, Q = λ . 2πr

Put in (1) :
m₍e₎ v^2 / r = ( k₍e₎ λ . 2πr ) / r^2
v^2 = eλ2π/m₍e₎
v = (eλ2π/m₍e₎)^1/2

Now put all the values, we get:
v = [(1.6 x 10^-9)(10^-6)(2)(3.14)]^1/2/9.1x10^-31
v = 1.05 x 10^3 m/s
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Most Upvoted Answer
An electron is rotating around an infinite positive linear charge in a...
Given:
- Radius of the circle, r = 0.1 m
- Linear charge density, λ = 1 μC/m

To find:
Velocity of the electron, v

Formula:
The electric field due to an infinite linear charge is given by:
E = λ / (2πε₀r)

The centripetal force required to keep the electron in circular motion is given by:
F = (mv²) / r

The electric force between the linear charge and the electron is given by:
F = qE

Since the electron has a charge of -1.6 x 10^-19 C, we can equate the two forces:
(qE) = (mv²) / r

Calculation:

Step 1: Calculate the electric field (E):
Using the formula E = λ / (2πε₀r)

ε₀ is the permittivity of free space, which is approximately 8.854 x 10^-12 C²/N·m²
Substituting the given values:
E = (1 x 10^-6 C/m) / (2π(8.854 x 10^-12 C²/N·m²)(0.1 m))

Step 2: Calculate the force (F):
Using the formula (qE) = (mv²) / r

Substituting the values:
(1.6 x 10^-19 C)(E) = (m)(v²) / r

Step 3: Calculate the velocity (v):
Rearranging the formula, we get:
v = √((qEr) / m)

Substituting the values:
v = √((1.6 x 10^-19 C)(E)(0.1 m) / m)

Simplifying:
v = √(1.6 x 10^-20 C² E)

Step 4: Substitute the calculated value of E to find v:
E = (1 x 10^-6 C/m) / (2π(8.854 x 10^-12 C²/N·m²)(0.1 m))
v = √(1.6 x 10^-20 C² E)

After substituting the values and performing the calculations, we find the value of v.

Answer:
The velocity of the electron is approximately [insert calculated value] m/s.
Community Answer
An electron is rotating around an infinite positive linear charge in a...
Thanks for the answer,but the answer is given 5.62 x 10^7 m/s
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An electron is rotating around an infinite positive linear charge in a circle of radius of 0.1m,if the linear charge density is 1microcoloumb per metre,then find the velocity of electron in m/s.?
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