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The identity (x+3)(x+4) = x² + 7x + 12 is true for
  • a)
    two values of x
  • b)
    one value of x
  • c)
    all value of x
  • d)
    None of Above
Correct answer is 'C'. Can you explain this answer?
Verified Answer
The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of...
We are looking for factors of 12 which ADD (becaus
e of + 12) up to 7.The signs will be the same (because of + 12), they are both negative (because of -7).The 
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Most Upvoted Answer
The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of...
Expanding the left side of the equation, we have:

(x 3)(x 4) = x(x 4) + 3(x 4) = x^2 4x + 3x + 12 = x^2 + 7x + 12

In order for this expression to be equal to x, we need to solve the equation:

x^2 + 7x + 12 = x

Rearranging the equation, we get:

x^2 + 6x + 12 = 0

Unfortunately, this equation does not have a solution that satisfies the given identity.
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The identity (x+3)(x+4) = x² + 7x + 12 is true fora)two values of xb)one value of xc)all value of xd)None of AboveCorrect answer is 'C'. Can you explain this answer?
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