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The following fig. shows I-V graph for a given metallic wire at two temperatures T1and T2.Then,
​
  • a)
    Temperature T2 is less
  • b)
    Temperature T2 is more
  • c)
    T1 is same as T2
  • d)
    None of the above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The following fig. shows I-V graph for a given metallic wire at two te...
The slope of the given graph gives us the inverse of resistance. Resistance of a material increases with increasing temperature because the collision between the molecules increases. 
In the graph given, T2 has a smaller slope and hence corresponds to higher resistance. Therefore, T2 > T1.
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Most Upvoted Answer
The following fig. shows I-V graph for a given metallic wire at two te...
h=vit.. or u can say heat is directly proportional to the product of v and i.. so for t1, i is increasing at a higher rate than v.. but for t2, v is increasing at a higher rate.. but the formula says that h is directly proportional to the product.. so product will almost remain constant for both.. so heat will be equal or t1=t2
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Community Answer
The following fig. shows I-V graph for a given metallic wire at two te...
The slope of the graph = I / V
In case of T2, I/V is less. Hence, V/I (=R) is more.
Value of resistance increases with increasing temperature. 
Hence, T2 >T
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The following fig. shows I-V graph for a given metallic wire at two temperatures T1and T2.Then, ​a)Temperature T2is lessb)Temperature T2is morec)T1is same as T2d)None of the aboveCorrect answer is option 'C'. Can you explain this answer?
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