Class 11 Exam > Class 11 Questions > A ball weighing 0.01kg hits a hard surface ve...
Start Learning for Free
A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball is
- a)1 N
- b)10 N
- c)100 N
- d)0.1 N
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A ball weighing 0.01kg hits a hard surface vertically with a speed of ...
Since impulse I = F x Δt
And also Impulse I = Δp (i.e. change in linear momentum)
Change in momentum
= 0.01 x 5 – (-5)
= 0.10 N s
Impulse = 0.10 N s
Therefore 0.10 = F x 0.01
Or F = 10 N
Most Upvoted Answer
A ball weighing 0.01kg hits a hard surface vertically with a speed of ...
Given:
Mass of the ball, m = 0.01 kg
Initial velocity, u = 5 m/s
Final velocity, v = -5 m/s (since the ball rebounds with the same speed in the opposite direction)
Time taken, t = 0.01 s
To find: Average force exerted by the surface, F
Formula used:
Average force, F = (change in momentum) / time taken
Change in momentum, Δp = m(v-u)
Calculation:
Δp = m(v-u)
Δp = 0.01 kg x (-5 m/s - 5 m/s)
Δp = -0.2 kg m/s (negative sign indicates the change in direction of momentum)
F = Δp / t
F = -0.2 kg m/s / 0.01 s
F = -20 N (negative sign indicates the force exerted by the surface is in the opposite direction of motion of the ball)
But we need to find the magnitude of the force, so we take the absolute value of the force:
|F| = 20 N
Therefore, the average force exerted by the surface on the ball is 20 N, which is closest to option (b) 10 N.
Mass of the ball, m = 0.01 kg
Initial velocity, u = 5 m/s
Final velocity, v = -5 m/s (since the ball rebounds with the same speed in the opposite direction)
Time taken, t = 0.01 s
To find: Average force exerted by the surface, F
Formula used:
Average force, F = (change in momentum) / time taken
Change in momentum, Δp = m(v-u)
Calculation:
Δp = m(v-u)
Δp = 0.01 kg x (-5 m/s - 5 m/s)
Δp = -0.2 kg m/s (negative sign indicates the change in direction of momentum)
F = Δp / t
F = -0.2 kg m/s / 0.01 s
F = -20 N (negative sign indicates the force exerted by the surface is in the opposite direction of motion of the ball)
But we need to find the magnitude of the force, so we take the absolute value of the force:
|F| = 20 N
Therefore, the average force exerted by the surface on the ball is 20 N, which is closest to option (b) 10 N.
Free Test
FREE
| Start Free Test |
Community Answer
A ball weighing 0.01kg hits a hard surface vertically with a speed of ...
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer?
Question Description
A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer?.
A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A ball weighing 0.01kg hits a hard surface vertically with a speed of 5m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01s. The average force exerted by the surface on the ball isa)1 Nb)10 Nc)100 Nd)0.1 NCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup