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If the electron in a hydrogen atom jumps from an orbit with level n1 = 2 to an orbit with level n2 = 1 the emitted radiation has a wavelength given by
- a)λ = 5/3R
- b)λ = 4/3 R
- c)λ = R/4
- d)λ = 3R/4
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
If the electron in a hydrogen atom jumps from an orbit with level n1 =...
656.3 nm
b) 486.1 nm
c) 434.0 nm
d) 410.2 nm
The correct answer is b) 486.1 nm.
This can be determined using the formula for the wavelength of emitted radiation:
λ = hc/ΔE
where λ is the wavelength, h is Planck's constant, c is the speed of light, and ΔE is the energy difference between the two levels.
The energy difference can be calculated using the formula:
ΔE = Rh(1/n1^2 - 1/n2^2)
where Rh is the Rydberg constant and n1 and n2 are the initial and final energy levels, respectively.
Plugging in the values for n1 and n2, we get:
ΔE = Rh(1/2^2 - 1/1^2) = 3Rh/4
Substituting this into the first formula, we get:
λ = hc/(3Rh/4)
Plugging in the values for h, c, and Rh, we get:
λ = (3 x 10^-7 m)(2.998 x 10^8 m/s)/(3(1.097 x 10^7 m^-1)/4)
λ = 486.1 nm
Therefore, the emitted radiation has a wavelength of 486.1 nm.
b) 486.1 nm
c) 434.0 nm
d) 410.2 nm
The correct answer is b) 486.1 nm.
This can be determined using the formula for the wavelength of emitted radiation:
λ = hc/ΔE
where λ is the wavelength, h is Planck's constant, c is the speed of light, and ΔE is the energy difference between the two levels.
The energy difference can be calculated using the formula:
ΔE = Rh(1/n1^2 - 1/n2^2)
where Rh is the Rydberg constant and n1 and n2 are the initial and final energy levels, respectively.
Plugging in the values for n1 and n2, we get:
ΔE = Rh(1/2^2 - 1/1^2) = 3Rh/4
Substituting this into the first formula, we get:
λ = hc/(3Rh/4)
Plugging in the values for h, c, and Rh, we get:
λ = (3 x 10^-7 m)(2.998 x 10^8 m/s)/(3(1.097 x 10^7 m^-1)/4)
λ = 486.1 nm
Therefore, the emitted radiation has a wavelength of 486.1 nm.
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Community Answer
If the electron in a hydrogen atom jumps from an orbit with level n1 =...
use the formula 1/lamda=R(1/n1^2-1/n2^2)Z^2 AND PUT N1=1 AND N2 =2 AND Z=1AND GET THE ANSWER
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If the electron in a hydrogen atom jumps from an orbit with level n1 = 2 to an orbit with level n2 = 1 the emitted radiation has a wavelength given bya)λ = 5/3Rb)λ = 4/3 Rc)λ= R/4d)λ = 3R/4Correct answer is option 'B'. Can you explain this answer?
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