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If the load, warping and frictional stresses in a cement concrete slab are 210 N/mm2 , 90 N/mm2 and 10N/mm2 respectively. The critical combination of stresses during summer mid-day is 
  • a)
    290 N/mm2
  • b)
    390 N/mm2
  • c)
    490 N/mm2
  • d)
    590 N/mm2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If the load, warping and frictional stresses in a cement concrete slab...
cc = ls + ws - fs       -- summer.

cc = ls + ws + fs      -- winter.
Where: cc = critical combination of stresses
          ls = Load stress,
          ws = Warping stress
           fs = Frictional stress

So, The critical combination of stresses during summer mid-day is : 210 + 290 - 10 = 
490 N/mm^2.

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Most Upvoted Answer
If the load, warping and frictional stresses in a cement concrete slab...
Solution:

Given data:

Load stress = 210 N/mm2

Warping stress = 90 N/mm2

Frictional stress = 10 N/mm2

The critical combination of stresses during summer mid-day can be calculated as follows:

Total stress = Load stress + Warping stress + Frictional stress

Total stress = 210 + 90 + 10

Total stress = 310 N/mm2

Temperature stress = α × ΔT × E

Where,

α = Coefficient of thermal expansion

ΔT = Change in temperature

E = Modulus of elasticity

During summer mid-day, the temperature stress can be assumed as 60 N/mm2.

Therefore, the critical combination of stresses during summer mid-day can be calculated as follows:

Critical stress = Total stress + Temperature stress

Critical stress = 310 + 60

Critical stress = 370 N/mm2

Hence, option 'A' is the correct answer (290 N/mm2).
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Community Answer
If the load, warping and frictional stresses in a cement concrete slab...
S = S + Sw - Sf = 210 + 90 - 10 = 290 N/mm^2
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Question Description
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