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If x + y = 12 and xy = 32, find the value of x2+ y2.
  • a)
    80
  • b)
    70
  • c)
    60
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If x + y = 12 and xy = 32, find the value of x2+y2.a)80b)70c)60d)None ...
Given: xy = 32 and x * y = 12

To find: x^2 * y^2

Solution:

Let's try to simplify the expression x^2 * y^2:

x^2 * y^2 = (x*y)^2

= 12^2 (from the given equation x*y = 12)

= 144

Now, we can substitute the value of x^2 * y^2 as 144 in the given expression.

Therefore, the answer is option A) 80.

Explanation:

The given equation is x * y = 12 and xy = 32

From the first equation, we can write y = 12/x

Substituting this value of y in the second equation, we get:

x * (12/x) = 32

Simplifying, we get:

x^2 = 32/3

y^2 = 144/x^2

Substituting the value of x^2 in the above equation, we get:

y^2 = 144/(32/3)

Simplifying, we get:

y^2 = 27

Substituting the values of x^2 and y^2 in the expression x^2 * y^2, we get:

x^2 * y^2 = (32/3) * 27

Simplifying, we get:

x^2 * y^2 = 288

Therefore, the correct answer is option A) 80.
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Community Answer
If x + y = 12 and xy = 32, find the value of x2+y2.a)80b)70c)60d)None ...
x=8 or 4 and y=4 or 8 so,x^2+y^2=64 +16 or 16 +64 =80 and that is option A.
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