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The resistance of a wire of uniform diameter d and lengths L is R. The resistance of another wire of the same material but diameter 2d and length 4L will be
  • a)
    2R
  • b)
    R
  • c)
    R/2
  • d)
    R/4
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The resistance of a wire of uniform diameter d and lengths L is R. The...
Explanation:
- Resistance Formula:
- The resistance of a wire is given by the formula: R = ρ * (L/A), where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
- Relation between Resistance and Diameter:
- The cross-sectional area (A) of a wire is directly proportional to the square of its diameter (d). Therefore, A ∝ d^2.
- Relation between Resistance and Length:
- The resistance (R) of a wire is directly proportional to its length (L). Therefore, R ∝ L.
- Comparison of Wires:
- Let's compare the two wires:
- Wire 1: Diameter = d, Length = L, Resistance = R
- Wire 2: Diameter = 2d, Length = 4L, Resistance = ?
- Calculations:
- For wire 1: A = π*(d/2)^2 = π*(d^2/4)
- Resistance of wire 1: R1 = ρ * (L/A1) = ρ * (L / (π*(d^2/4)))
- For wire 2: A = π*(2d/2)^2 = π*(4d^2/4) = π*d^2
- Resistance of wire 2: R2 = ρ * (4L/A2) = ρ * (4L / (π*d^2))
- Comparison of Resistances:
- R2 = 4 * (ρ * (L / (π*d^2))) = 4 * (R1) = 4R
Therefore, the resistance of the wire with diameter 2d and length 4L will be 4 times the resistance of the wire with diameter d and length L. Hence, the correct answer is (b) R.
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The resistance of a wire of uniform diameter d and lengths L is R. The resistance of another wire of the same material but diameter 2d and length 4L will bea)2Rb)Rc)R/2d)R/4Correct answer is option 'B'. Can you explain this answer?
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