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If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​
  • a)
    The values are both precise and accurate
  • b)
    The value are neither precise nor accurate
  • c)
    The values are accurate
  • d)
    The values are precise
Correct answer is option 'D'. Can you explain this answer?
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If the true value for a result is 2.00 g and a student takes 2 measure...
Precision indicates how closely repeated measurements match each other. Since both the values are close to each other, they are precise and since their is a difference between the mean value and true value, they are not accurate.

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If the true value for a result is 2.00 g and a student takes 2 measure...
Both experimental values are close to each other but are not close to true value.
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If the true value for a result is 2.00 g and a student takes 2 measure...
Precision and Accuracy:
In the context of measurements, precision refers to the degree of agreement or reproducibility between individual measurements, while accuracy refers to the closeness of a measurement to the true value. Let's analyze the given measurements to determine their precision and accuracy.

Measurement 1:
The first measurement reported by the student is 1.95 g. Since the true value is 2.00 g, we can calculate the percent error as follows:

Percent Error = [(Measured Value - True Value) / True Value] * 100
= [(1.95 - 2.00) / 2.00] * 100
= (-0.05 / 2.00) * 100
= -2.5%

Measurement 2:
The second measurement reported by the student is 1.93 g. Again, we can calculate the percent error:

Percent Error = [(Measured Value - True Value) / True Value] * 100
= [(1.93 - 2.00) / 2.00] * 100
= (-0.07 / 2.00) * 100
= -3.5%

Precision:
To determine the precision, we examine the degree of agreement or reproducibility between the two measurements. In this case, the measurements differ by 0.02 g (1.95 g - 1.93 g), indicating that they are not identical. However, the difference between the measurements is quite small, suggesting a relatively high degree of precision.

Accuracy:
To assess accuracy, we compare the measurements to the true value. Both measurements are slightly lower than the true value (2.00 g), resulting in negative percent errors (-2.5% and -3.5%). These negative percent errors indicate that the measurements underestimate the true value.

Conclusion:
Given that the measurements are not identical but only differ by a small amount, we can conclude that they are precise. However, since the measurements underestimate the true value, they are not accurate. Therefore, the correct answer is option 'D': The values are precise.
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If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​a)The values are both precise and accurateb)The value are neither precise nor accuratec)The values are accurated)The values are preciseCorrect answer is option 'D'. Can you explain this answer?
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If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​a)The values are both precise and accurateb)The value are neither precise nor accuratec)The values are accurated)The values are preciseCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​a)The values are both precise and accurateb)The value are neither precise nor accuratec)The values are accurated)The values are preciseCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​a)The values are both precise and accurateb)The value are neither precise nor accuratec)The values are accurated)The values are preciseCorrect answer is option 'D'. Can you explain this answer?.
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