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Which of the following is not accumulated by the body of living organisms?
  • a)
    Oxygen
  • b)
    Carbon dioxide
  • c)
    Urea
  • d)
    Ammonia
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Which of the following is not accumulated by the body of living organi...
Accumulation of Oxygen in Living Organisms:
Living organisms do not accumulate oxygen in their bodies as it is primarily used in the process of respiration to produce energy. Oxygen is inhaled by organisms for cellular respiration where it reacts with glucose to produce ATP, the energy currency of the cell. Any excess oxygen that is not immediately used in respiration is expelled through exhalation.

Accumulation of Carbon Dioxide, Urea, and Ammonia:
- Carbon Dioxide: Carbon dioxide is a waste product of cellular respiration and is accumulated in the body until it is exhaled through respiration.
- Urea: Urea is a waste product formed in the liver as a result of protein metabolism. It is then transported to the kidneys where it is excreted in urine.
- Ammonia: Ammonia is a toxic waste product produced by the breakdown of proteins and amino acids. It is converted into urea in the liver and excreted from the body through urine.
In conclusion, while living organisms do not accumulate oxygen in their bodies, they do accumulate carbon dioxide, urea, and ammonia as waste products that need to be efficiently eliminated from the body to maintain proper functioning.
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Community Answer
Which of the following is not accumulated by the body of living organi...
Oxygen is not accumulated by the body of living organisms as this is required by the cells to perform respiration. Also, it is not a waste product of the cells. Animals accumulate ammonia, urea, uric acid, carbon dioxide, water, and ions like Na+, K+, Cl, phosphate, sulphate, etc., by certain metabolic activities.
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Which of the following is not accumulated by the body of living organisms?a)Oxygenb)Carbon dioxidec)Uread)AmmoniaCorrect answer is option 'A'. Can you explain this answer?
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