JEE Exam > JEE Questions > A compound contain 69.5% oxygen and 30.5% nit...
Start Learning for Free
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound is
- a)N2O
- b)NO2
- c)N2O4
- d)N2O5
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular w...
Explanation:
- First, we need to find the empirical formula of the compound based on the given percentages of oxygen and nitrogen.
- Assume we have 100g of the compound, which means it contains 69.5g of oxygen and 30.5g of nitrogen.
Calculating moles of oxygen and nitrogen:
- Moles of oxygen = 69.5g / 16g/mol (molecular weight of oxygen) = 4.34 mol
- Moles of nitrogen = 30.5g / 14g/mol (molecular weight of nitrogen) = 2.18 mol
Divide by the smallest number of moles:
- Oxygen: 4.34 mol / 2.18 mol = 2
- Nitrogen: 2.18 mol / 2.18 mol = 1
Empirical formula: N2O4 (2 nitrogen atoms and 4 oxygen atoms)
- The molecular weight of N2O4 can be calculated as:
2(N) + 4(O) = 2(14) + 4(16) = 28 + 64 = 92
- Since the given molecular weight of the compound is 92, the empirical formula N2O4 matches the molecular weight given.
Therefore, the correct formula of the compound is N2O4.
- First, we need to find the empirical formula of the compound based on the given percentages of oxygen and nitrogen.
- Assume we have 100g of the compound, which means it contains 69.5g of oxygen and 30.5g of nitrogen.
Calculating moles of oxygen and nitrogen:
- Moles of oxygen = 69.5g / 16g/mol (molecular weight of oxygen) = 4.34 mol
- Moles of nitrogen = 30.5g / 14g/mol (molecular weight of nitrogen) = 2.18 mol
Divide by the smallest number of moles:
- Oxygen: 4.34 mol / 2.18 mol = 2
- Nitrogen: 2.18 mol / 2.18 mol = 1
Empirical formula: N2O4 (2 nitrogen atoms and 4 oxygen atoms)
- The molecular weight of N2O4 can be calculated as:
2(N) + 4(O) = 2(14) + 4(16) = 28 + 64 = 92
- Since the given molecular weight of the compound is 92, the empirical formula N2O4 matches the molecular weight given.
Therefore, the correct formula of the compound is N2O4.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?
Question Description
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?.
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?.
Solutions for A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A compound contain 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound isa)N2Ob)NO2c)N2O4d)N2O5Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup