JEE Exam > JEE Questions > The reaction, CH = CH-CH + HBr → CHCHBr ...
Start Learning for Free
The reaction, CH₂ = CH-CH₃ + HBr → CH₃CHBr - CH₃ is
- a)Nucleophilic addition
- b)Electrophilic substitution
- c)Electrophilic addition
- d)Free radical addition
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Nucleophilic Addition
- Nucleophilic addition involves the attack of a nucleophile on an electrophilic center resulting in the formation of a new bond.
- In the given reaction, HBr acts as a nucleophile attacking the electron-deficient carbon-carbon double bond.
- The nucleophilic attack leads to the formation of a new bond between carbon and hydrogen, resulting in the addition of HBr across the double bond.
Electrophilic Substitution
- Electrophilic substitution involves the replacement of an atom or group in a molecule by an electrophile.
- In the given reaction, there is no substitution of any atom or group in the molecule.
- Instead, a new bond is formed through the addition of HBr across the double bond.
Electrophilic Addition
- Electrophilic addition involves the addition of an electrophile to a pi bond, resulting in the formation of a new sigma bond.
- In the given reaction, the double bond in CH=CH-CH acts as a pi bond and undergoes electrophilic addition with HBr to form CHCHBr-CH.
- Therefore, the reaction can be classified as an electrophilic addition reaction.
Free Radical Addition
- Free radical addition involves the addition of free radicals to unsaturated compounds.
- In the given reaction, there is no involvement of free radicals in the addition of HBr across the double bond.
- Hence, the reaction is not a free radical addition reaction.
- Nucleophilic addition involves the attack of a nucleophile on an electrophilic center resulting in the formation of a new bond.
- In the given reaction, HBr acts as a nucleophile attacking the electron-deficient carbon-carbon double bond.
- The nucleophilic attack leads to the formation of a new bond between carbon and hydrogen, resulting in the addition of HBr across the double bond.
Electrophilic Substitution
- Electrophilic substitution involves the replacement of an atom or group in a molecule by an electrophile.
- In the given reaction, there is no substitution of any atom or group in the molecule.
- Instead, a new bond is formed through the addition of HBr across the double bond.
Electrophilic Addition
- Electrophilic addition involves the addition of an electrophile to a pi bond, resulting in the formation of a new sigma bond.
- In the given reaction, the double bond in CH=CH-CH acts as a pi bond and undergoes electrophilic addition with HBr to form CHCHBr-CH.
- Therefore, the reaction can be classified as an electrophilic addition reaction.
Free Radical Addition
- Free radical addition involves the addition of free radicals to unsaturated compounds.
- In the given reaction, there is no involvement of free radicals in the addition of HBr across the double bond.
- Hence, the reaction is not a free radical addition reaction.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?
Question Description
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?.
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup