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The reaction, CH₂ = CH-CH₃ + HBr → CH₃CHBr - CH₃ is
- a)Nucleophilic addition
- b)Electrophilic substitution
- c)Electrophilic addition
- d)Free radical addition
Correct answer is option 'C'. Can you explain this answer?
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Nucleophilic Addition
- Nucleophilic addition involves the attack of a nucleophile on an electrophilic center resulting in the formation of a new bond.
- In the given reaction, HBr acts as a nucleophile attacking the electron-deficient carbon-carbon double bond.
- The nucleophilic attack leads to the formation of a new bond between carbon and hydrogen, resulting in the addition of HBr across the double bond.
Electrophilic Substitution
- Electrophilic substitution involves the replacement of an atom or group in a molecule by an electrophile.
- In the given reaction, there is no substitution of any atom or group in the molecule.
- Instead, a new bond is formed through the addition of HBr across the double bond.
Electrophilic Addition
- Electrophilic addition involves the addition of an electrophile to a pi bond, resulting in the formation of a new sigma bond.
- In the given reaction, the double bond in CH=CH-CH acts as a pi bond and undergoes electrophilic addition with HBr to form CHCHBr-CH.
- Therefore, the reaction can be classified as an electrophilic addition reaction.
Free Radical Addition
- Free radical addition involves the addition of free radicals to unsaturated compounds.
- In the given reaction, there is no involvement of free radicals in the addition of HBr across the double bond.
- Hence, the reaction is not a free radical addition reaction.
- Nucleophilic addition involves the attack of a nucleophile on an electrophilic center resulting in the formation of a new bond.
- In the given reaction, HBr acts as a nucleophile attacking the electron-deficient carbon-carbon double bond.
- The nucleophilic attack leads to the formation of a new bond between carbon and hydrogen, resulting in the addition of HBr across the double bond.
Electrophilic Substitution
- Electrophilic substitution involves the replacement of an atom or group in a molecule by an electrophile.
- In the given reaction, there is no substitution of any atom or group in the molecule.
- Instead, a new bond is formed through the addition of HBr across the double bond.
Electrophilic Addition
- Electrophilic addition involves the addition of an electrophile to a pi bond, resulting in the formation of a new sigma bond.
- In the given reaction, the double bond in CH=CH-CH acts as a pi bond and undergoes electrophilic addition with HBr to form CHCHBr-CH.
- Therefore, the reaction can be classified as an electrophilic addition reaction.
Free Radical Addition
- Free radical addition involves the addition of free radicals to unsaturated compounds.
- In the given reaction, there is no involvement of free radicals in the addition of HBr across the double bond.
- Hence, the reaction is not a free radical addition reaction.
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?
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