The angle between the line (x + 1)/3 = (y - 1)/2 = (z - 2)/4 and the p...
Line Equation and Plane Equation:
The equation of the line is given by (x + 1)/3 = (y - 1)/2 = (z - 2)/4.
The equation of the plane is given by 2x + y - 3z + 4 = 0.
Angle between Line and Plane:
To find the angle between the line and the plane, we need to find the direction ratios of the line and the normal vector of the plane.
The direction ratios of the line are 3, 2, and 4. Therefore, the direction vector of the line is (3, 2, 4).
The coefficients of x, y, and z in the equation of the plane give us the normal vector to the plane, which is (2, 1, -3).
Angle Calculation:
The angle between the line and the plane can be found using the dot product formula:
cosθ = (a · b) / (|a| * |b|),
where a and b are the direction vector of the line and the normal vector of the plane, respectively.
Substituting the values, we get:
cosθ = (3*2 + 2*1 + 4*(-3)) / (√(3^2 + 2^2 + 4^2) * √(2^2 + 1^2 + (-3)^2)),
cosθ = (-4) / (√(29) * √(14)).
Therefore, the angle between the line and the plane is cos⁻¹(-4/√(406)), which is not provided as an option. Hence, the correct answer is option 'D'.