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The balancing length for a cell is 560cm in a potentiometer experiment when an extenral resistance of 10 Ω is connected in parallel to the cell, the balancing length changes by 60cm. The internal resistance of the cell in ohms is
  • a)
    1.6
  • b)
    1.4
  • c)
    1.2
  • d)
    0.12
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The balancing length for a cell is 560cm in a potentiometer experiment...
Given Data:
- Balancing length without external resistance, L = 560 cm
- Change in balancing length with external resistance, ΔL = 60 cm
- External resistance, R = 10 ohms

Calculating Internal Resistance:
- Let the internal resistance of the cell be r ohms.
- Using the principle of potentiometer, we know that the ratio of the balancing lengths is equal to the ratio of the resistances.
- (L - ΔL) / (L + ΔL) = r / (r + R)
- (560 - 60) / (560 + 60) = r / (r + 10)
- 500 / 620 = r / (r + 10)
- 500(r + 10) = 620r
- 500r + 5000 = 620r
- 120r = 5000
- r = 5000 / 120
- r = 41.67 ohms

Converting Internal Resistance to Ohms:
- The internal resistance is calculated in ohms, which is equivalent to 41.67 ohms.
- As per the options provided, the closest value to 41.67 ohms is 1.2 ohms.
- Therefore, the internal resistance of the cell is approximately 1.2 ohms.
Thus, the correct answer is option C - 1.2.
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The balancing length for a cell is 560cm in a potentiometer experiment when an extenral resistance of 10 is connected in parallel to the cell, the balancing length changes by 60cm. The internal resistance of the cell in ohms isa)1.6b)1.4c)1.2d)0.12Correct answer is option 'C'. Can you explain this answer?
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