For what real value of y will matrix A be equal to matrix B, where

a)
11, 3

b)
No real value

c)
1/3, 1/2

d)
2 and 3

Correct answer is option 'B'. Can you explain this answer?

Question

For what real value of y will matrix A be equal to matrix B, where a)11, 3b)No real valuec)1/3, 1/2d)2 and 3Correct answer is option 'B'. Can you explain this answer?

Answer

y^2-4y+3=0 (y-1)(y-3)=0 y=1,3

Answer

Answer

Hint:-solve 5y=6y^2+1 & y^2-4y=-3

Answer

As both matrix are eaual given so each element are equal y^2-4y=-3
y^2 -3y-y+3=0
y(y-3)-1(y-3)=0
y-1=0, y-3=0
y=1,3 similarly on solving other quadratic equation on y we get
y=1/3,1/2
no common value so no real value

Answer

(5y = 6y^2+1) (6y^2 - 5y +1 = 0) apply shri dharacharya method nd solve u will get 1/2 nd1/3 which is not real HENCE OPTION b IS CORRECT

Answer

Answer

Y must satisfy  both conditions 5y=6y(square)+1y(square)-4y=-3Which  is not possible  to have real  number  that's  why answer  is option B

Answer

Y2-4y=-3 on solving we get y=1,3
6y2-5y+1=0 on solving we get y=1/3,1/2
there is no common value so y is not real .

Answer

Comparing the elements of matrices A and B, we get two different sets of values of y, where nothing is common. So, we can say that no real values exist satisfying the given matrices. Note that it doesn't mean that values obtained are not real.

Answer

Yes no real value should be correct answer

Answer

Matrix

https://edurev.in/studytube/Matrix/aacba2ae-e890-4506-b8d7-e4bd34a868a9_t

Answer

No real value

Answer

Consider y*y-4y =-3

y*y-4y+3=0

factors are -1,-3
=> y-3=0 ; y=3
y-1=0; y=1
a)

Answer

No real value.

Answer

Answer

Why

Answer

How 1 and 3 are not real numbers?

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