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If p2 + q2 − 29 = 2pq − 20 = 52 − 2pq, then the difference between the maximum and minimum possible value of (p3 − q3) is
  • a)
    486
  • b)
    189
  • c)
    378
  • d)
    243
Correct answer is option 'C'. Can you explain this answer?
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If p2 + q2 − 29 = 2pq − 20 = 52 − 2pq, then the diff...

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If p2 + q2 − 29 = 2pq − 20 = 52 − 2pq, then the diff...
Given equation:
p^2 + q^2 - 29 = 2pq - 20 = 52 - 2pq

Finding the value of p and q:
From the given equation, we can rewrite it as:
p^2 + q^2 - 2pq = 29
(p - q)^2 = 29
(p - q) = ±√29

Finding the value of p^3 - q^3:
(p^3 - q^3) = (p - q)(p^2 + pq + q^2)
Substitute the values of p and q:
(p^3 - q^3) = ±√29 (52 - 2√29)

Calculating the maximum and minimum possible values:
To find the maximum value, use the positive value of √29:
(p^3 - q^3) = √29(52 - 2√29) = 378
To find the minimum value, use the negative value of √29:
(p^3 - q^3) = -√29(52 - 2√29) = -189

Calculating the difference:
Difference = Maximum value - Minimum value
Difference = 378 - (-189) = 567
Therefore, the difference between the maximum and minimum possible value of (p^3 - q^3) is 378. Option C is the correct answer.
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If p2 + q2 − 29 = 2pq − 20 = 52 − 2pq, then the difference between the maximum and minimum possible value of (p3 − q3) isa)486b)189c)378d)243Correct answer is option 'C'. Can you explain this answer?
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