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The focal lengths of the objective and eye lenses of a telescope are 200 cm and 5 cm respectively. The maximum power of the telescope will be
  • a)
    40
  • b)
    48
  • c)
    60
  • d)
    100
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The focal lengths of the objective and eye lenses of a telescope are 2...
Calculation of Maximum Power of Telescope:

Focal Length of Objective Lens (fo):
- Given: fo = 200 cm

Focal Length of Eye Lens (fe):
- Given: fe = 5 cm

Formula for Magnifying Power (M) of Telescope:
M = - fo / fe

Calculation:
M = - 200 cm / 5 cm
M = - 40

Maximum Power of Telescope:
- The maximum power of a telescope is the reciprocal of the magnifying power.
- Therefore, Maximum Power = 1 / |M|
- Maximum Power = 1 / 40
- Maximum Power = 0.025

Conversion to Diopters:
- Since power is measured in diopters, we convert the value by taking the reciprocal.
- Maximum Power (in Diopters) = 1 / Maximum Power
- Maximum Power (in Diopters) = 1 / 0.025
- Maximum Power (in Diopters) = 40 Diopters
Therefore, the maximum power of the telescope is 40 Diopters, which corresponds to option B.
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The focal lengths of the objective and eye lenses of a telescope are 200 cm and 5 cm respectively. The maximum power of the telescope will bea)40b)48c)60d)100Correct answer is option 'B'. Can you explain this answer?
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