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Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearly
- a)1.6×10-19 m/s2
- b)9.1×1031 m/s2
- c)1.5×1019 m/s2
- d)1.6×1027 m/s2
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Under the action of a given coulombic force the acceleration of an ele...
Given, acceleration of an electron under a given coulombic force = 2.51022 m/s2.
We know that, the force experienced by a charged particle due to another charged particle is given by Coulomb's law,
F = k*q1*q2/r^2
where, F = force, k = Coulomb's constant, q1 and q2 are the charges of the particles and r is the distance between them.
Since the coulombic force is same for both electron and proton, we can write,
k*q1*q2/r^2 = k*q1*q2/r^2
or q1*q2 = q*e (where e is the charge of an electron)
Now, we know that the mass of an electron (me) is much smaller than the mass of a proton (mp). Hence, we can assume that the force acting on both the particles is the same but the acceleration of the particles will depend on their mass.
Using Newton's second law of motion, F = m*a, we can write the acceleration of a proton as,
a = F/mp
where F is the same coulombic force acting on both the particles.
Substituting the values, we get
a = k*q*e/(mp * r^2)
Given, a = 2.51022 m/s2 for electron
Substituting the values, we get
mp/me = a*e/a*p
or a*p = a*e *me/mp
Substituting the values, we get
a*p = 2.51022 * 9.10938356E-31/1.6726219E-27
a*p = 1.50959E19 m/s2
Hence, the magnitude of the acceleration of a proton under the same force is approximately 1.51019 m/s2.
Therefore, the correct answer is option 'C'.
We know that, the force experienced by a charged particle due to another charged particle is given by Coulomb's law,
F = k*q1*q2/r^2
where, F = force, k = Coulomb's constant, q1 and q2 are the charges of the particles and r is the distance between them.
Since the coulombic force is same for both electron and proton, we can write,
k*q1*q2/r^2 = k*q1*q2/r^2
or q1*q2 = q*e (where e is the charge of an electron)
Now, we know that the mass of an electron (me) is much smaller than the mass of a proton (mp). Hence, we can assume that the force acting on both the particles is the same but the acceleration of the particles will depend on their mass.
Using Newton's second law of motion, F = m*a, we can write the acceleration of a proton as,
a = F/mp
where F is the same coulombic force acting on both the particles.
Substituting the values, we get
a = k*q*e/(mp * r^2)
Given, a = 2.51022 m/s2 for electron
Substituting the values, we get
mp/me = a*e/a*p
or a*p = a*e *me/mp
Substituting the values, we get
a*p = 2.51022 * 9.10938356E-31/1.6726219E-27
a*p = 1.50959E19 m/s2
Hence, the magnitude of the acceleration of a proton under the same force is approximately 1.51019 m/s2.
Therefore, the correct answer is option 'C'.
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Community Answer
Under the action of a given coulombic force the acceleration of an ele...
as we know; F= ma
for electron:
F = mass of electron X acceleration
F = 9.1*10^(-31) X 2.5*20^22
the force is same for proton also as stated above
so,
F = mass of proton X acceleration
so, acceleration = force/(mass of proton)
hence, acceleration = 9.1*10^(-31) X 2.5*20^22/1.67*10^(-27)
The calculated value matches option 'C'.
I Hope it helps!
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Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer?
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Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer?.
Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer?.
Solutions for Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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ample number of questions to practice Under the action of a given coulombic force the acceleration of an electron is 2.5×1022 m/s2. Then the magnitude of the acceleration of a proton under the action of same force is nearlya)1.6×10-19 m/s2b)9.1×1031 m/s2c)1.5×1019 m/s2d)1.6×1027 m/s2Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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