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2-Methylbutane on reacting with bromine in the presence of sunlight gives mainly
- a)1-bromo-3-methylbutane
- b)2-bromo-3-methylbutane
- c)2-bromo-2-methylbutane
- d)1-bromo-2-methylbutane
Correct answer is option 'C'. Can you explain this answer?
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2-Methylbutane on reacting with bromine in the presence of sunlight gi...
Reaction of 2-Methylbutane with Bromine
When 2-methylbutane reacts with bromine in the presence of sunlight, the reaction proceeds through a free radical mechanism.
Major Product Formed
The major product formed in this reaction is 2-bromo-2-methylbutane.
Explanation
- The reaction involves the abstraction of a hydrogen atom from the 2-methylbutane molecule by a bromine radical, forming a methyl radical.
- This methyl radical can then attack a bromine molecule to form the 2-bromo-2-methylbutane product.
- This product is the major product because the radical intermediate formed during the reaction is stabilized by the presence of a tertiary carbon, leading to a higher yield of the desired product.
Conclusion
Hence, when 2-methylbutane reacts with bromine in the presence of sunlight, the main product obtained is 2-bromo-2-methylbutane due to the stability of the radical intermediate formed during the reaction.
When 2-methylbutane reacts with bromine in the presence of sunlight, the reaction proceeds through a free radical mechanism.
Major Product Formed
The major product formed in this reaction is 2-bromo-2-methylbutane.
Explanation
- The reaction involves the abstraction of a hydrogen atom from the 2-methylbutane molecule by a bromine radical, forming a methyl radical.
- This methyl radical can then attack a bromine molecule to form the 2-bromo-2-methylbutane product.
- This product is the major product because the radical intermediate formed during the reaction is stabilized by the presence of a tertiary carbon, leading to a higher yield of the desired product.
Conclusion
Hence, when 2-methylbutane reacts with bromine in the presence of sunlight, the main product obtained is 2-bromo-2-methylbutane due to the stability of the radical intermediate formed during the reaction.
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2-Methylbutane on reacting with bromine in the presence of sunlight gi...
Reaction of 2-Methylbutane with Bromine in the Presence of Sunlight
- Mechanism of Reaction:
- The reaction between 2-Methylbutane and bromine in the presence of sunlight undergoes a free radical substitution reaction.
- The bromine molecule is homolytically cleaved by the sunlight, forming bromine radicals.
- The 2-Methylbutane molecule also undergoes homolytic cleavage to form a methyl radical and a butyl radical.
- Product Formation:
- The butyl radical attacks a bromine radical, leading to the formation of 2-bromo-2-methylbutane as the major product.
- This is due to the fact that the butyl radical is more stable compared to the methyl radical, leading to the preferential formation of 2-bromo-2-methylbutane.
- Conclusion:
- Therefore, the main product obtained from the reaction of 2-Methylbutane with bromine in the presence of sunlight is 2-bromo-2-methylbutane.
- Mechanism of Reaction:
- The reaction between 2-Methylbutane and bromine in the presence of sunlight undergoes a free radical substitution reaction.
- The bromine molecule is homolytically cleaved by the sunlight, forming bromine radicals.
- The 2-Methylbutane molecule also undergoes homolytic cleavage to form a methyl radical and a butyl radical.
- Product Formation:
- The butyl radical attacks a bromine radical, leading to the formation of 2-bromo-2-methylbutane as the major product.
- This is due to the fact that the butyl radical is more stable compared to the methyl radical, leading to the preferential formation of 2-bromo-2-methylbutane.
- Conclusion:
- Therefore, the main product obtained from the reaction of 2-Methylbutane with bromine in the presence of sunlight is 2-bromo-2-methylbutane.
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2-Methylbutane on reacting with bromine in the presence of sunlight gives mainlya)1-bromo-3-methylbutaneb)2-bromo-3-methylbutanec)2-bromo-2-methylbutaned)1-bromo-2-methylbutaneCorrect answer is option 'C'. Can you explain this answer?
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