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2-Methylbutane on reacting with bromine in the presence of sunlight gives mainly
- a)1-bromo-3-methylbutane
- b)2-bromo-3-methylbutane
- c)2-bromo-2-methylbutane
- d)1-bromo-2-methylbutane
Correct answer is option 'C'. Can you explain this answer?
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2-Methylbutane on reacting with bromine in the presence of sunlight gi...
Reaction of 2-Methylbutane with Bromine
When 2-methylbutane reacts with bromine in the presence of sunlight, the reaction proceeds through a free radical mechanism.
Major Product Formed
The major product formed in this reaction is 2-bromo-2-methylbutane.
Explanation
- The reaction involves the abstraction of a hydrogen atom from the 2-methylbutane molecule by a bromine radical, forming a methyl radical.
- This methyl radical can then attack a bromine molecule to form the 2-bromo-2-methylbutane product.
- This product is the major product because the radical intermediate formed during the reaction is stabilized by the presence of a tertiary carbon, leading to a higher yield of the desired product.
Conclusion
Hence, when 2-methylbutane reacts with bromine in the presence of sunlight, the main product obtained is 2-bromo-2-methylbutane due to the stability of the radical intermediate formed during the reaction.
When 2-methylbutane reacts with bromine in the presence of sunlight, the reaction proceeds through a free radical mechanism.
Major Product Formed
The major product formed in this reaction is 2-bromo-2-methylbutane.
Explanation
- The reaction involves the abstraction of a hydrogen atom from the 2-methylbutane molecule by a bromine radical, forming a methyl radical.
- This methyl radical can then attack a bromine molecule to form the 2-bromo-2-methylbutane product.
- This product is the major product because the radical intermediate formed during the reaction is stabilized by the presence of a tertiary carbon, leading to a higher yield of the desired product.
Conclusion
Hence, when 2-methylbutane reacts with bromine in the presence of sunlight, the main product obtained is 2-bromo-2-methylbutane due to the stability of the radical intermediate formed during the reaction.
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2-Methylbutane on reacting with bromine in the presence of sunlight gi...
Reaction of 2-Methylbutane with Bromine in the Presence of Sunlight
- Mechanism of Reaction:
- The reaction between 2-Methylbutane and bromine in the presence of sunlight undergoes a free radical substitution reaction.
- The bromine molecule is homolytically cleaved by the sunlight, forming bromine radicals.
- The 2-Methylbutane molecule also undergoes homolytic cleavage to form a methyl radical and a butyl radical.
- Product Formation:
- The butyl radical attacks a bromine radical, leading to the formation of 2-bromo-2-methylbutane as the major product.
- This is due to the fact that the butyl radical is more stable compared to the methyl radical, leading to the preferential formation of 2-bromo-2-methylbutane.
- Conclusion:
- Therefore, the main product obtained from the reaction of 2-Methylbutane with bromine in the presence of sunlight is 2-bromo-2-methylbutane.
- Mechanism of Reaction:
- The reaction between 2-Methylbutane and bromine in the presence of sunlight undergoes a free radical substitution reaction.
- The bromine molecule is homolytically cleaved by the sunlight, forming bromine radicals.
- The 2-Methylbutane molecule also undergoes homolytic cleavage to form a methyl radical and a butyl radical.
- Product Formation:
- The butyl radical attacks a bromine radical, leading to the formation of 2-bromo-2-methylbutane as the major product.
- This is due to the fact that the butyl radical is more stable compared to the methyl radical, leading to the preferential formation of 2-bromo-2-methylbutane.
- Conclusion:
- Therefore, the main product obtained from the reaction of 2-Methylbutane with bromine in the presence of sunlight is 2-bromo-2-methylbutane.
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2-Methylbutane on reacting with bromine in the presence of sunlight gives mainlya)1-bromo-3-methylbutaneb)2-bromo-3-methylbutanec)2-bromo-2-methylbutaned)1-bromo-2-methylbutaneCorrect answer is option 'C'. Can you explain this answer?
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2-Methylbutane on reacting with bromine in the presence of sunlight gives mainlya)1-bromo-3-methylbutaneb)2-bromo-3-methylbutanec)2-bromo-2-methylbutaned)1-bromo-2-methylbutaneCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 2-Methylbutane on reacting with bromine in the presence of sunlight gives mainlya)1-bromo-3-methylbutaneb)2-bromo-3-methylbutanec)2-bromo-2-methylbutaned)1-bromo-2-methylbutaneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2-Methylbutane on reacting with bromine in the presence of sunlight gives mainlya)1-bromo-3-methylbutaneb)2-bromo-3-methylbutanec)2-bromo-2-methylbutaned)1-bromo-2-methylbutaneCorrect answer is option 'C'. Can you explain this answer?.
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