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If x2+1/x2=18 then find the value of x-/x?
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If x2+1/x2=18 then find the value of x-/x?
Given Equation:
x² + 1/x² = 18

Finding the Value of x - 1/x:
To find the value of x - 1/x, we need to express x² + 1/x² in terms of (x - 1/x)².

Expanding (x - 1/x)²:
(x - 1/x)² = x² - 2 + 1/x²
(x - 1/x)² = x² + 1/x² - 2

Substitute the Given Value:
(x - 1/x)² = 18 - 2
(x - 1/x)² = 16

Finding the Value of x - 1/x:
Taking the square root of both sides:
x - 1/x = ±4
Therefore, the value of x - 1/x is ±4.
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If x2+1/x2=18 then find the value of x-/x?
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