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The temperature of a body falls from 50oC to 40oC in 10 minutes. If the temperature of the surroundings is 20oC Then temperature of the body after another 10 minutes will be
  • a)
    36.6oC
  • b)
    33.3oC
  • c)
    35oC
  • d)
    30oC
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The temperature of a body falls from 50oC to 40oC in 10 minutes. If th...
Given data:
Initial temperature of the body (T1) = 50oC
Final temperature of the body (T2) = 40oC
Temperature of surroundings (To) = 20oC
Time interval = 10 minutes

Formula used:
Newton's Law of Cooling states that the rate of change of temperature of an object is directly proportional to the difference between its temperature and the temperature of its surroundings.

Calculation:
1. Calculate the rate of change of temperature (k):
T1 - To = (T2 - To)e^(-kt)
50 - 20 = (40 - 20)e^(-10k)
30 = 20e^(-10k)
1.5 = e^(-10k)
-ln(1.5) = -10k
k ≈ 0.0513
2. Calculate the temperature after another 10 minutes:
T = To + (T1 - To)e^(-kt)
T = 20 + (50 - 20)e^(-0.0513*10)
T ≈ 33.3oC
Therefore, the temperature of the body after another 10 minutes will be 33.3oC, which is option 'B'.
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