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A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocity
  • a)
    100 m/s in the horizontal direction
  • b)
    300 m/s in the horizontal direction
  • c)
    300 m/s in a direction making an angle of 60° with the horizontal
  • d)
    200 m/s in a direction making an angle of 60° with the horizontal
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A cannon ball is fired with a velocity 200 m/sec at an angle of 60°...
Analysis:
The given scenario involves a cannonball being fired at an angle of 60° with the horizontal and then splitting into three equal fragments at the highest point of its flight.

Fragment Movement Analysis:
- One fragment moves vertically upwards with a velocity of 100 m/s.
- Another fragment moves vertically downwards with a velocity of 100 m/s.
- The third fragment's horizontal velocity can be calculated using the principle of conservation of momentum.

Conservation of Momentum:
- Initially, the cannonball is moving with a velocity of 200 m/s at an angle of 60° with the horizontal.
- At the highest point of its flight, the total momentum of the fragments must be equal to the initial momentum of the cannonball.
- Since the fragments split equally, the horizontal component of the momentum is conserved.

Calculating Horizontal Velocity:
- The horizontal component of the initial velocity = 200 * cos(60°) = 100 m/s.
- The horizontal component of the third fragment's velocity should also be 100 m/s.
- Therefore, the third fragment will be moving with a velocity of 300 m/s in the horizontal direction.
Therefore, the correct answer is option 'B) 300 m/s in the horizontal direction'.
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A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer?
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