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A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocity
- a)100 m/s in the horizontal direction
- b)300 m/s in the horizontal direction
- c)300 m/s in a direction making an angle of 60° with the horizontal
- d)200 m/s in a direction making an angle of 60° with the horizontal
Correct answer is option 'B'. Can you explain this answer?
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A cannon ball is fired with a velocity 200 m/sec at an angle of 60°...
Analysis:
The given scenario involves a cannonball being fired at an angle of 60° with the horizontal and then splitting into three equal fragments at the highest point of its flight.
Fragment Movement Analysis:
- One fragment moves vertically upwards with a velocity of 100 m/s.
- Another fragment moves vertically downwards with a velocity of 100 m/s.
- The third fragment's horizontal velocity can be calculated using the principle of conservation of momentum.
Conservation of Momentum:
- Initially, the cannonball is moving with a velocity of 200 m/s at an angle of 60° with the horizontal.
- At the highest point of its flight, the total momentum of the fragments must be equal to the initial momentum of the cannonball.
- Since the fragments split equally, the horizontal component of the momentum is conserved.
Calculating Horizontal Velocity:
- The horizontal component of the initial velocity = 200 * cos(60°) = 100 m/s.
- The horizontal component of the third fragment's velocity should also be 100 m/s.
- Therefore, the third fragment will be moving with a velocity of 300 m/s in the horizontal direction.
Therefore, the correct answer is option 'B) 300 m/s in the horizontal direction'.
The given scenario involves a cannonball being fired at an angle of 60° with the horizontal and then splitting into three equal fragments at the highest point of its flight.
Fragment Movement Analysis:
- One fragment moves vertically upwards with a velocity of 100 m/s.
- Another fragment moves vertically downwards with a velocity of 100 m/s.
- The third fragment's horizontal velocity can be calculated using the principle of conservation of momentum.
Conservation of Momentum:
- Initially, the cannonball is moving with a velocity of 200 m/s at an angle of 60° with the horizontal.
- At the highest point of its flight, the total momentum of the fragments must be equal to the initial momentum of the cannonball.
- Since the fragments split equally, the horizontal component of the momentum is conserved.
Calculating Horizontal Velocity:
- The horizontal component of the initial velocity = 200 * cos(60°) = 100 m/s.
- The horizontal component of the third fragment's velocity should also be 100 m/s.
- Therefore, the third fragment will be moving with a velocity of 300 m/s in the horizontal direction.
Therefore, the correct answer is option 'B) 300 m/s in the horizontal direction'.
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A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer?
Question Description
A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer?.
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Solutions for A cannon ball is fired with a velocity 200 m/sec at an angle of 60° with the horizontal. At the highest point of its flight it explodes into 3 equal fragments, one going vertically upwards with velocity 100 m/sec, the second one falling vertically downwards with a velocity 100 m/sec. The third fragment will be moving with a velocitya)100 m/s in the horizontal directionb)300 m/s in the horizontal directionc)300 m/s in a direction making an angle of 60° with the horizontald)200 m/s in a direction making an angle of 60° with the horizontalCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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