JEE Exam > JEE Questions > Which of the following samples of reducing ag...
Start Learning for Free
Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.
- a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+
- b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04
- c)25 ml of 0.1 M H202 to be oxidized to H+ and 02
- d)25 ml of 0.1 M SnCl2 to be oxidized to S04+
Correct answer is option 'A,D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Which of the following samples of reducing agents is /are chemically e...
Understanding Reducing Agents
To determine which reducing agents are chemically equivalent to 25 ml of 0.2 N KMnO4, we need to understand the concept of normality and the stoichiometry involved in redox reactions.
Normalized KMnO4 Reaction
- KMnO4 is a strong oxidizing agent and in acidic medium, it reduces to Mn²⁺.
- The equivalent factor for KMnO4 in this reaction is 5 because 1 mole of KMnO4 can accept 5 moles of electrons.
Calculating Equivalents
- For 25 ml of 0.2 N KMnO4:
- Equivalents = Normality × Volume (L) = 0.2 N × 0.025 L = 0.005 equivalents
Now, let's analyze each option:
Option A: 25 ml of 0.2 M FeSO4
- Oxidation: Fe²⁺ → Fe³⁺
- 1 mole of Fe²⁺ gives 1 mole of electrons, thus:
- Equivalents = Molarity × Volume (L) = 0.2 M × 0.025 L = 0.005 equivalents
- This matches the equivalents from KMnO4.
Option B: 50 ml of 0.1 M H3AsO3
- Oxidation: H3AsO3 → H3AsO4
- 1 mole of H3AsO3 gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.050 L = 0.005 equivalents, but since it gives 2 electrons, it would actually provide 0.010 equivalents, making it unsuitable.
Option C: 25 ml of 0.1 M H2O2
- Oxidation: H2O2 → H⁺ + O₂
- 1 mole of H2O2 gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.025 L = 0.0025 equivalents, insufficient to match.
Option D: 25 ml of 0.1 M SnCl2
- Oxidation: Sn²⁺ → Sn⁴⁺
- 1 mole of Sn²⁺ gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.025 L = 0.0025 equivalents, but since it provides 2 electrons, it gives 0.005 equivalents, matching the requirement.
Conclusion
Thus, the chemically equivalent reducing agents to 25 ml of 0.2 N KMnO4 are:
- **Option A: FeSO4**
- **Option D: SnCl2**
To determine which reducing agents are chemically equivalent to 25 ml of 0.2 N KMnO4, we need to understand the concept of normality and the stoichiometry involved in redox reactions.
Normalized KMnO4 Reaction
- KMnO4 is a strong oxidizing agent and in acidic medium, it reduces to Mn²⁺.
- The equivalent factor for KMnO4 in this reaction is 5 because 1 mole of KMnO4 can accept 5 moles of electrons.
Calculating Equivalents
- For 25 ml of 0.2 N KMnO4:
- Equivalents = Normality × Volume (L) = 0.2 N × 0.025 L = 0.005 equivalents
Now, let's analyze each option:
Option A: 25 ml of 0.2 M FeSO4
- Oxidation: Fe²⁺ → Fe³⁺
- 1 mole of Fe²⁺ gives 1 mole of electrons, thus:
- Equivalents = Molarity × Volume (L) = 0.2 M × 0.025 L = 0.005 equivalents
- This matches the equivalents from KMnO4.
Option B: 50 ml of 0.1 M H3AsO3
- Oxidation: H3AsO3 → H3AsO4
- 1 mole of H3AsO3 gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.050 L = 0.005 equivalents, but since it gives 2 electrons, it would actually provide 0.010 equivalents, making it unsuitable.
Option C: 25 ml of 0.1 M H2O2
- Oxidation: H2O2 → H⁺ + O₂
- 1 mole of H2O2 gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.025 L = 0.0025 equivalents, insufficient to match.
Option D: 25 ml of 0.1 M SnCl2
- Oxidation: Sn²⁺ → Sn⁴⁺
- 1 mole of Sn²⁺ gives 2 moles of electrons.
- Equivalents = 0.1 M × 0.025 L = 0.0025 equivalents, but since it provides 2 electrons, it gives 0.005 equivalents, matching the requirement.
Conclusion
Thus, the chemically equivalent reducing agents to 25 ml of 0.2 N KMnO4 are:
- **Option A: FeSO4**
- **Option D: SnCl2**
Free Test
FREE
| Start Free Test |
Community Answer
Which of the following samples of reducing agents is /are chemically e...
No
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer?
Question Description
Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer?.
Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer?.
Solutions for Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer?, a detailed solution for Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? has been provided alongside types of Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Which of the following samples of reducing agents is /are chemically equivalent to 25 ml of 0.2 N KMnO4 to be reduced to Mn2+ and water.a)25 ml of 0.2 M FeSO4 to be oxidized to Fe3+b)50 ml of 0.1 M H3AsO3 to be oxidized to H3As04c)25 ml of 0.1 M H202 to be oxidized to H+ and 02d)25 ml of 0.1 M SnCl2 to be oxidized to S04+Correct answer is option 'A,D'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup