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A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram?
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A fixed beam AB of spam 5m carries a uniformly distributed load of 20k...
Calculating Fixed End Moments:
- To calculate the fixed end moments, we will first determine the reactions at the supports.
- The total load acting on the beam can be found by summing up the uniformly distributed load and the concentrated load:
Total Load = (20kN/m * 2.5m) + 40kN = 90kN
- Taking moments about point A:
90kN * 5m - 40kN * 1m - Rb * 5m = 0
Rb = 46kN
- Summing forces in the vertical direction:
Ra + Rb - 90kN = 0
Ra = 44kN
- Now, we can calculate the fixed end moments using the reaction forces and the span of the beam.
Calculating Fixed End Moment at A:
- For the fixed end moment at A, we will consider the reaction at A and the total load acting on the beam.
- Taking moments about B:
Ma = Rb * 5m - 90kN * 2.5m
Ma = 230kNm
Calculating Fixed End Moment at B:
- For the fixed end moment at B, we will consider the reaction at B and the total load acting on the beam.
- Taking moments about A:
Mb = 90kN * 5m - Ra * 5m
Mb = 50kNm
Drawing Bending Moment Diagram:
- To draw the bending moment diagram, we will plot the fixed end moments at A and B and analyze the changes in bending moment along the length of the beam.
- At point A (x=0), the bending moment is 230kNm.
- Between A and the point of the concentrated load (x=4m), the bending moment will decrease linearly.
- At the point of the concentrated load (x=4m), there will be a sudden increase of 40kN * 1m = 40kNm.
- Between the point of the concentrated load and B (x=5m), the bending moment will decrease linearly from 40kNm to 50kNm at B.
By following these steps, you can accurately calculate the fixed end moments and draw the bending moment diagram for the given beam.
- To calculate the fixed end moments, we will first determine the reactions at the supports.
- The total load acting on the beam can be found by summing up the uniformly distributed load and the concentrated load:
Total Load = (20kN/m * 2.5m) + 40kN = 90kN
- Taking moments about point A:
90kN * 5m - 40kN * 1m - Rb * 5m = 0
Rb = 46kN
- Summing forces in the vertical direction:
Ra + Rb - 90kN = 0
Ra = 44kN
- Now, we can calculate the fixed end moments using the reaction forces and the span of the beam.
Calculating Fixed End Moment at A:
- For the fixed end moment at A, we will consider the reaction at A and the total load acting on the beam.
- Taking moments about B:
Ma = Rb * 5m - 90kN * 2.5m
Ma = 230kNm
Calculating Fixed End Moment at B:
- For the fixed end moment at B, we will consider the reaction at B and the total load acting on the beam.
- Taking moments about A:
Mb = 90kN * 5m - Ra * 5m
Mb = 50kNm
Drawing Bending Moment Diagram:
- To draw the bending moment diagram, we will plot the fixed end moments at A and B and analyze the changes in bending moment along the length of the beam.
- At point A (x=0), the bending moment is 230kNm.
- Between A and the point of the concentrated load (x=4m), the bending moment will decrease linearly.
- At the point of the concentrated load (x=4m), there will be a sudden increase of 40kN * 1m = 40kNm.
- Between the point of the concentrated load and B (x=5m), the bending moment will decrease linearly from 40kNm to 50kNm at B.
By following these steps, you can accurately calculate the fixed end moments and draw the bending moment diagram for the given beam.
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A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram?
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A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram?.
A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fixed beam AB of spam 5m carries a uniformly distributed load of 20kN/m run over the left half and a concentrated load of 40kN at a distance of 4m from the left support. Calculate fixed end moments and hence draw the Bending Moment alongwith Diagram?.
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