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Find range of sin2x + sinx + cosx?
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Find range of sin2x + sinx + cosx?
Range of sin2x sinx cosx


Let's first break down the expression sin2x sinx cosx:



  • sin2x = 2sinx cosx (using the double angle identity)

  • sin2x sinx cosx = 2sinx cosx * sinx cosx = 2sin^2x cos^2x



Now, we can rewrite the expression as:



  • 2sin^2x cos^2x = sin^2x (2cos^2x) = cos^2x (2sin^2x)



Since both sin^2x and cos^2x are always between 0 and 1, we know that:



  • 2sin^2x cos^2x is always between 0 and 1

  • sin^2x (2cos^2x) is always between 0 and 1

  • cos^2x (2sin^2x) is always between 0 and 1



Therefore, the range of sin2x sinx cosx is:



  • 0 ≤ sin2x sinx cosx ≤ 1



This means that the expression can take any value between 0 and 1, inclusive.
Community Answer
Find range of sin2x + sinx + cosx?
Sinx + cosx = 2sinxcosx
also sin2x= 2sinx cox
adding both we get 4sinxcosx
which is equal to 2sin2x
range = [-2,2]
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Find range of sin2x + sinx + cosx?
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