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2x^2-5/6x+1/12 factorise it?
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2x^2-5/6x+1/12 factorise it?
2x^2-5/6x+1/12 

Multiplying the eq. by 12 we get

24x^2-10x+1

Now by middle term splitting method

24x^2-6x-4x+1 6x(4x-1) -1 (4x-1).

Taking 4x-1 common (6x-1) (4x-1)
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2x^2-5/6x+1/12 factorise it?
Factorising 2x^2 - (5/6)x + (1/12)

Step 1: Find the common factor (if any)

In order to factorise the given expression, we need to check if there is a common factor among the terms. Here, we can see that all three terms have a common factor of 1/6. We can factor out this common factor:

1/6(2x^2 - (5/6)x + (1/12))

Step 2: Factorise the quadratic term

Now, we need to factorise the quadratic term (2x^2 - (5/6)x + (1/12)). To do this, we can use the quadratic formula or look for two binomials that multiply to give the quadratic expression.

The quadratic expression 2x^2 - (5/6)x + (1/12) can be factored as:

2x^2 - (5/6)x + (1/12) = (2x - 1/4)(x - 1/3)

Step 3: Combine the factors

Now that we have factored the quadratic term, we can combine it with the common factor we found earlier:

1/6(2x - 1/4)(x - 1/3)

Final Answer:

The given expression 2x^2 - (5/6)x + (1/12) can be factorised as 1/6(2x - 1/4)(x - 1/3).
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2x^2-5/6x+1/12 factorise it?
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